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3 years ago

Prove that tan² theta + cot² theta = sec² theta cosec² theta- 2

Mathematics

1 answer:

wel3 years ago

4 0

Step-by-step explanation:

Tan² theta = sec² theta - 1

Cot² theta = cosec² theta - 1

Tan²+Cot² = sec²-1+cosec²-1

= sec²+cosec²-2

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The sum of two consecutive odd integers is 680 what are the integers

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Answer:

let the first number and second number be x+1 and x+3 respectively

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2 years ago

Dakari makes 2 dozen jars of jam. The total weight of all of the filled jars is 211.2 ounces. When empty, each jar weighs 1.2 ou

Rzqust [24]

Answer:

Step-by-step explanation:

Total weight of all of the filled jars with jam = 211.2 ounces

When empty, each jar weighs 1.2 ounces

Total weight of 2 dozens of empty jar = 24 × 1.2 ounces

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Total weight of jam in 2 dozens jar = Total weight of all of the filled jars with jam - Total weight of 2 dozens of empty jar

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3 years ago

Jamie has $30 in a savings account. The interest rate is 10% per year and is not

erastova [34]

Answer:

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Step-by-step explanation:

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8 0

3 years ago

Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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3 years ago

Find the missing measure for a right circular cone given the following information. Find L.A. if r = 6 and h = 8 48 60 96

svetlana [45]

$\bf \textit{lateral area of a cone}\\\\
LA=\pi r\sqrt{r^2+h^2}\quad 
\begin{cases}
r=radius\\
h=height\\
-----\\
r=6\\
h=8
\end{cases}\implies LA=\pi(6)\sqrt{6^2+8^2}
\\\\\\
LA=6\pi \sqrt{100}\implies LA=6\pi (10)\implies LA=60\pi$

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4 years ago

Prove that tan² theta + cot² theta = sec² theta cosec² theta- 2​

Prove that tan² theta + cot² theta = sec² theta cosec² theta- 2