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Gnom [1K]
3 years ago
7

One number is three more than a second number. Three times the first is 13 less than 5 times the second.

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

14 and 11

let x be the second number then the first number = x + 3 ( 3 more than second)

Also 3(x + 3) = 5x - 13

3x + 9 = 5x - 13

subtract 3x from both sides

9 = 5x - 3x - 13

9 = 2x - 13

add 13 to both sides

22 = 2x

divide both sides by 2

11 = x → second number

first number = x + 3 = 11 + 3 = 14


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Maths!
Ber [7]

Answer:

(1) Variance = 4.5 and Standard deviation = 2.121.

(2) Variance = 4.5 and Standard deviation = 2.121.

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged.

Step-by-step explanation:

We are given with the following set of data below;

              X                     X-\bar X                   (X-\bar X)^{2}

              5                   5 - 8 = -3                     9

              5                   5 - 8 = -3                     9

              8                   8 - 8 = 0                      0

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

             10                  10 - 8 = 2                     4

              9                   9 - 8 = 1                       1

              9                   9 - 8 = 1                       1

         <u>     6     </u>              6 - 8 = -2             <u>        4       </u>          

Total <u>    72     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{72}{9}  = 8

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                        =  \sqrt{4.5} = 2.12

(2) Now, each value is added by 2; so the new data set is given by;

              X                     X-\bar X                   (X-\bar X)^{2}

              7                   7 - 10 = -3                     9

              7                   7 - 10 = -3                     9

             10                  10 - 10 = 0                     0

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

             12                  12 - 10 = 2                     4

              11                  11 - 10 = 1                       1

              11                  11 - 10 = 1                       1

         <u>     8     </u>              8 - 10 = -2             <u>        4       </u>          

Total <u>    90     </u>                                         <u>       36       </u>

<u>Firstly, the mean of the above data is given by;</u>

              Mean, \bar X  =  \frac{\sum X}{n}

                              =  \frac{90}{9}  = 10

(1)Now, the variance of the given data is;

            Variance  =  \frac{\sum (X-\bar X)^{2} }{n-1}

                                  =  \frac{36}{9-1}  = 4.5

So, the new standard deviation, (S.D.)  =  \sqrt{\text{Variance}}

                                                                =  \sqrt{4.5} = 2.12

(3) The effect on the measure of dispersion if each value is changed uniformly ​is that it remains unchanged as we see in the case of variance or standard deviation.

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Step-by-step explanation:

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