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Gnom [1K]
3 years ago
7

One number is three more than a second number. Three times the first is 13 less than 5 times the second.

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

14 and 11

let x be the second number then the first number = x + 3 ( 3 more than second)

Also 3(x + 3) = 5x - 13

3x + 9 = 5x - 13

subtract 3x from both sides

9 = 5x - 3x - 13

9 = 2x - 13

add 13 to both sides

22 = 2x

divide both sides by 2

11 = x → second number

first number = x + 3 = 11 + 3 = 14


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b) Null hypothesis: \mu =69.5

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And we can use a t test procedure in order to check if the true mean is equat to the desired value.

Step-by-step explanation:

For this case we know that this:

Claim: The mean pulse rate​ (in beats per​ minute) of adult males is equal to 69.5 bpm

Part a

If we convert this with symbols we can write this as:

\mu =69.5

Part b

We have the following info given:

\bar X= 69.9 represent the sample mean

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We have the following system of hypothesis:

Null hypothesis: \mu =69.5

Alternative hypothesis: \mu \neq 69.5

And we can use a t test procedure in order to check if the true mean is equat to the desired value.

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