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Gnom [1K]
3 years ago
7

One number is three more than a second number. Three times the first is 13 less than 5 times the second.

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

14 and 11

let x be the second number then the first number = x + 3 ( 3 more than second)

Also 3(x + 3) = 5x - 13

3x + 9 = 5x - 13

subtract 3x from both sides

9 = 5x - 3x - 13

9 = 2x - 13

add 13 to both sides

22 = 2x

divide both sides by 2

11 = x → second number

first number = x + 3 = 11 + 3 = 14


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Simita has 25 coins, consisting of 10c and 5c, which total $2.25. how many of each does she have?​
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Answer:

10c = 20

5c = 5

Step-by-step explanation:

Let x be the number of 10c coins; let y be the number of 5c coins. The total is $2.25, so the amount of 10c and 5c coins will add to that. Simita has 25 coins, so x and y, the number of coins, will have to add to 25. Hence, solve the simultaneous equation.

10x + 5y = 225 (1) - times by 0

x + y = 25 (2) - times by 5

10x + 5y = 225 (1)

5x + 5y = 125 (2)

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Substitute x back into the original equation.

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