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charle [14.2K]
3 years ago
11

Which angle is adjacent to A. B. C. D.

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
Angles A F and E should be the answer
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If you used 0.5 ml of sample and 2.5 ml of diluent what is your dilution ratio?
Vikki [24]

Answer:

1/6

Step-by-step explanation:

I think it is:

0.5/(0.5+2.5) = 0.5/3 = 1/6

6 0
3 years ago
What is the length of segment A’B’?
Klio2033 [76]

Answer:

8

Step-by-step explanation:

A translation is a solid transformation. Lengths of sides and measures of angle remain equal.

6 0
2 years ago
Suppose a change of coordinates T:R2→R2 from the uv-plane to the xy-plane is given by x=e−2ucos(5v), y=e−2usin(5v). Find the abs
anzhelika [568]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The solution is  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

Step-by-step explanation:

From the question we are told that

        x =  e^{-2a} cos (5v)

and  y  =  e^{-2a} sin(5v)

Generally the absolute value of the determinant of the Jacobian for this change of coordinates is mathematically evaluated as

     | \frac{\delta  (x,y)}{\delta (u, v)} | =  | \ det \left[\begin{array}{ccc}{\frac{\delta x}{\delta u} }&{\frac{\delta x}{\delta v} }\\\frac{\delta y}{\delta u}&\frac{\delta y}{\delta v}\end{array}\right] |

        = |\ det\ \left[\begin{array}{ccc}{-2e^{-2u} cos(5v)}&{-5e^{-2u} sin(5v)}\\{-2e^{-2u} sin(5v)}&{-2e^{-2u} cos(5v)}\end{array}\right]  |

Let \   a =  -2e^{-2u} cos(5v),  \\ b=-2e^{-2u} sin(5v),\\c =-2e^{-2u} sin(5v),\\d=-2e^{-2u} cos(5v)

So

     \frac{\delta  (x,y)}{\delta (u, v)} | = |det  \left[\begin{array}{ccc}a&b\\c&d\\\end{array}\right] |

=>    \frac{\delta  (x,y)}{\delta (u, v)} | = | a *  b  - c* d |

substituting for a, b, c,d

=>    \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 (e^{-2u})^2 cos^2 (5v) - 10 e^{-4u} sin^2(5v)|

=>   \frac{\delta  (x,y)}{\delta (u, v)} | =  | -10 e^{-4u} (cos^2 (5v)   + sin^2 (5v))|

=>  \frac{\delta  (x,y)}{\delta (u, v)} | = 10e^{-4u}

7 0
3 years ago
Help plz I've been stuck
stepladder [879]

Answer:

The answer is D. (\frac{1}{5} )^{2}

Step-by-step explanation:

5^{4} *(5^{-3} )^{2}

simplify the expression by multiplying

5^{4} *5^{-6}

calculate the product

5^{-2}

express with a positive exponent using a^{-n} =\frac{1}{a^{n} }

\frac{1}{5^{2} }

6 0
3 years ago
Read 2 more answers
-b+- square root of (b*b) -4ac/2a
Jet001 [13]
This is the quadratic formula.
7 0
3 years ago
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