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Lisa [10]
3 years ago
8

You need a loan for $1000, and you can take this loan out with Company A or Company B. Company A charges an 8% interest rate and

needs to be paid off in 5 years. Company B charges a 5% interest rate and needs to be paid off in 8 years. Which company should you get a loan from and why?
Mathematics
1 answer:
Wittaler [7]3 years ago
5 0

Answer: Company b

Step-by-step explanation:

because company B is only 5percent it is better and can pay in 8 years

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Simplify this expression. <br> 6x2(3x)<br><br> 18x2 <br><br> 18x3<br><br> 108x2<br><br> 108x3
vazorg [7]
A) 18x2 = 36



hope I helped 
Best of luck :)
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3 years ago
What is the percent error in using 3.14 as an approximation of pi
inessss [21]
Pi is an irrational number meaning it has no end, 3.14 is just an estimate which means that it is not accurate.
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So I have another math question that involves the same problem and so is 7 + 7x the same as 7x+ 7 i think it is but i'm not sure
BartSMP [9]

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Step-by-step explanation:

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6 0
2 years ago
Read 2 more answers
All vectors are in Rn. Check the true statements below:
Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

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B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that ||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then ||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||.

C) Consider S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2. This set is orthogonal because (0,2)\cdot(2,0)=0(2)+2(0)=0, but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in \mathbb{R}^n. Then the columns of A form an orthonormal set. We have that A^{-1}=A^t. To see this, note than the component b_{ij} of the product A^t A is the dot product of the i-th row of A^t and the jth row of A. But the i-th row of A^t is equal to the i-th column of A. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then A^t A=I    

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set \{u_1,u_2\cdots u_p\} and suppose that there are coefficients a_i such that a_1u_1+a_2u_2\cdots a_nu_n=0. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then a_i||u_i||=0 then a_i=0.  

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3 years ago
When four times a number n is decreased by 3 it’s at most 21
pashok25 [27]
The number is = 6
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