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slamgirl [31]
3 years ago
10

What is the answer 1/4x-6=3/5

Mathematics
2 answers:
nalin [4]3 years ago
8 0
♥ <span>Add 6 to both sides.
♥ </span><span>Multiply both sides by 4.
</span><span>♥ x=<span>132/<span>5</span></span></span>
Kipish [7]3 years ago
6 0
The answer to 1/4x - 6 = 3/5 is x = 132/5, or if you want to simplify it to a mixed fraction, it'd be 26 2/5. Here are the steps:

1/4x - 6 = 3/5

        +6     +6  Add 6 to each side to isolate the variable x.

1/4x      = 6 3/5

(4)1/4x  = 6 3/5(4) Multiply by 1/4's reciprocal (4), to isolate the variable x.

x            = 33/5 (4)

x            = 132/5

x            = 26 2/5
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WILL MARK BRAINLEIST
lina2011 [118]

Answer:

decrease by 50%

Step-by-step explanation:

\frac{0.4x}{0.8y} =\frac{x}{2y}      

Decreased by 60% = (100%-60%)x = 0.4x.

Decreased by 20% = (100%-20%)x = 0.8x.

\frac{x}{y} initial fraction, and we can see that denominator will increase 2 times, so fraction will decrease 2 times, or decrease by 50%.

6 0
3 years ago
Explain why the triangles are similar. Then find the value of x.
djyliett [7]
Answer: Choice A) AA postulate; 18

---------------------------------------------------------------------------------------

Work Shown:

The triangles are similar to each other due to the AA (angle angle) postulate. The top angles are overlapping or shared angles. So that's the first pair. The second pair of angles is either bottom pair of angles, from the fact that corresponding angles are congruent. This is only true if the lines are parallel.

Due to the similar triangles, we can set up the proportion and solve for x
8/(8+4) = 12/x
8/12 = 12/x
8*x = 12*12 ... cross multiply
8x = 144
x = 144/8
x = 18

8 0
3 years ago
Geometry math question no Guessing and Please show work
galina1969 [7]

here ZLS defines a line segment with end points Z and S.

so it represents line segment ZS

So option B is correct

4 0
3 years ago
2. Write the expressions using an exponent. Then solve.
Maurinko [17]
B. Five cubed because there at 5 2s there and 2*2*2*2*2 would be the same thing as saying 5^2
7 0
3 years ago
Read 2 more answers
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
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