We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
13/8 = 1 5/8
Step-by-step explanation:
first make 3 1/4 into an improper fraction
3 1/4 = (3*4+1)/4 = 13/4
13/4 /2
we know that dividing by a number is multiplying by its reciprocal, so
(13/4)/2 = 13/4 * (1/2)
multiply the numerators together, and multiply the denominators together
13/4 * (1/2) = (13*1)/(4*2) = 13/8 = 1 5/8
4. 3(y + 4y) this is distributive property! Hope it helps. Btw can you please check out a question on my page? thanks!! <span />
Answer:
2328.5 weeks or 6.4 years
Step-by-step explanation:
69855/30= 2328.5/365= 6.4
D,F, E i think these are it
