The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.
Answer:
The slope-intercept is (0, 6).
Answer:
y=-5/2x+4
Step-by-step explanation:
find the slope by using y2-y1/x2-x1
-1-19/2-(-4)
simplify
-20/8
simplify
-5/2
use slope-intercept form, y=mx+b
since we know the slope, find b
plug in one of the ordered pairs into the equation
-1=(-5/2)(2)+b
simplify
-1= -10/2+b
simplify
-1=-5+b
add 5 to both sides
b=4
plug b into y=-5/2x+b
y=-5/2x+4
39. FALSE
40. Where is the answer?
