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4 years ago

How do properties of integer exponents help you write equivalent expressions

1 answer:

7 0

When writing equivalent expressions, there are often several possible orders in which to simplify them. However, they will all take you to the same result as long as you do not make a mistake when using the properties. In this example, you will distribute the outer exponent first using the Power of a Product Property.

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Which of the following represent a linear inequality in open-sentence form? (Select all that apply.) 2x - 7y > 10, 3 < 5,

IrinaK [193]

The answer would be 8 + x > 5.

Hope this helps! :)

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3 years ago

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two nearby towns have a population of 442,680 and 564,943. what is the total population of both towns

stellarik [79]

1007623 is the answer because 442680 plus 564943 is 1007623

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3 years ago

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A company performs linear regressions to compare data sets of two similar products. If the residuals for brand A form an increas

Radda [10]

I think the correct answer would be B. If the residuals for brand A form an increasing curve, and the residuals for brand B form a U-shaped pattern, then neither of the data is likely to be linear. In order to be linear, the residuals of both data set should be, more or less, linear or approaching linearity in nature. Therefore, the linear regression that was done would not give good results since it is only applicable to linear data sets. Also, you can say that the relation of the data sets of the products are not linear. It would be best to do a curve fitting for both sets by using different functions like parabolic functions.

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3 years ago

Given that x is a hypergeometric random variable with Nequals10, nequals4, and requals6, complete parts a through d. a. Compu

sergey [27]

Answer:

a. 0.114

b. 0.005

c. 0.381

d. 0.00

Step-by-step explanation:

If x follows a hypergeometric distribution, the probability that x is equal to k is calculated as:

$P(x=k)=\frac{(rCk)*((N-r)C(n-k))}{NCn}$

Where k≤r and n-k≤N-r, Additionally:

$aCb=\frac{a!}{b!(a-b)!}$

So, replacing N by 10, n by 4 and r by 6, we get:

$P(x=k)=\frac{6Ck*((10-6)C(4-k))}{10C4}=\frac{6Ck*(4C(4-k))}{10C4}$

Then, the probability that x is equal to 1, P(x=1) is:

$P(x=1)=\frac{6C1*4C3}{10C4}=0.114$

The probability that x is equal to 0, P(x=0) is:

$P(x=0)=\frac{6C0*4C4}{10C4}=0.005$

The probability that x is equal to 3, P(x=3) is:

$P(x=3)=\frac{6C3*4C1}{10C4}=0.381$

Finally, in this case, x can take values from 0 to 4, so the probability that x is greater or equals to 5 is zero.

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3 years ago

A small combination lock on a suitcase has 3 wheels, each labeled with the 10 digits from 0 to 9. If an opening combination is

Artyom0805 [142]

Answer:

0.14% probability of a person guessing the right combination

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the numbers are selected is important. For example, 1,3,2 is a different combination than 3,1,2. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$