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Xelga [282]
3 years ago
5

Edgar wants to plot the ordered pair 1.8 -1.2 ona coordinate plane. On each axis one grid square equals 0.1. starting atb the th

e orgin how can edgar find
Mathematics
1 answer:
cluponka [151]3 years ago
6 0
What is ONA and ATB like really
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Plz plz plz help me out!!
slava [35]
Henry swims at 1.6 laps per minute, Larry swims at 1.8 laps per minute. Larry swims faster
6 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
3 years ago
A soccer ball is kicked toward the goal. The height of the ball is modeled by the function h(t) = −16t2 + 48t where t equals the
zlopas [31]
1. The function h(t)=-16t^{2}+48t is a parabola of the form ax^{2}+bx. The the formula for the axis of symmetry of a parabola is x= \frac{-b}{2a}. We can infer from our function that a=-16 and b=48, so lets replace those values in our formula:
x= \frac{-b}{2a}
x= \frac{-48}{-2(16)}
x= \frac{-48}{-32}
x= \frac{3}{2}
x=1.5
We can conclude that to the left of the line of symmetry the ball is reaching its maximum height, and to the right of the line of symmetry the ball is falling.

2. Lets check how much time the ball takes to reach its maximum height and return to the ground. To do that we are going to set the height equal to zero:
0=-16t^{2}+48t
-16t(t-3)=0
t=0 or t-3=0
t=0 or t=3
From our previous point we know that the ball reaches its maximum time at t=1.5, which means that <span>it takes 1.5 seconds to reach the maximum height and 1.5 seconds to fall back to the ground.</span>

7 0
3 years ago
Read 2 more answers
Find the slope of the line passing through the points (2,-9) and )1,-3)
nignag [31]

Hi there!

\large\boxed{\text{slope =} 6}

We can calculate slope using the following formula:

slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Plug in the corresponding points:

slope = \frac{-9-(-3)}{2-1}

Simplify:

slope = \frac{-6}{1} = -6

3 0
3 years ago
Read 2 more answers
40 POINTS Geometry homework
kicyunya [14]

\angle{DBC   }=(5x+4)°

\angle{ A  }=(2x-2)°

\angle{C   }=(4x-6)°

we know that,

\angle{DBC}=\angle{A}+\angle{C}

According to the question,

\tt{ 5x+4=2x-2+4x-6  }

\tt{ 5x+4=6x-8  }

\tt{ 6x-5x=4+8  }

\blue{x=12   }

so,

\angle{C }=(4x-6)°=(4×12-6)°=(48-6)°=42°

6 0
3 years ago
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