Question

Kate is arranging new furniture in her rectangular sitting room. She has mapped the arrangement on a coordinate pane. A,B and C represent the sofas, V1 and V2 are decorative vases and AQ the aquarium. Find the distance between V1 and the aquarium.
Please help any body thank you

Answer 1

Answer:

11 units

Step-by-step explanation:

Given : She has mapped the arrangement on a coordinate pane. A,B and C represent the sofas, V1 and V2 are decorative vases and AQ the aquarium

To Find: The distance between V1 and the aquarium.

Solution:

Referring the given image

We can have the coordinates of V1 and AQ

Coordinates of V1 :$(x_{1}, y_{1}) =(-6,5)$

Coordinates of AQ :$(x_{2}, y_{2}) =(5,5)$

Now To find distance use distance formula

$d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

$d=\sqrt{(5-[-6])^{2} + (5-5)^{2}}$

$d=\sqrt{11)^{2} + (0)^{2}}$

$d=\sqrt{11)^{2}}$

$d=\sqrt{121}$

$d=11$

Hence The distance between V1 and the aquarium is 11 units

Answer 2

Answer:

Step-by-step explanation:

11 is not a choice so i chose the choice that said 12