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Bezzdna [24]
3 years ago
6

7th grade Girl!

Mathematics
1 answer:
nika2105 [10]3 years ago
4 0
Answer:

A, P, M, S, W, Q


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<em>So to solve for a variable, you have to isolate that variable onto one side.</em>

<h3>14.</h3>

Firstly, multiply both sides by j: h-4=kj

Next, divide both sides by k and <u>your answer will be: \frac{h-4}{k}=j</u>

<h3>15.</h3>

Firstly, add g on both sides: \frac{x}{5}=a+g

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3 years ago
To which subset of the real number system does the number 1.5¯(repeating decimal)  belong to?
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8 0
3 years ago
Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m
Molodets [167]

Answer:

\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

Step-by-step explanation:

We want to find \lim_{x \to 2^-} \frac{|x-2|}{x-2}.

By definition:

|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1).

The limit of a constant is the constant.

\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1.

8 0
3 years ago
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