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Sergio039 [100]

3 years ago

12

I NEED HELP ASAP number 1 and 4

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

Answer:

i'm sorry i need help too

Step-by-step explanation:

i have no points

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9.1(6)+8.7(7)=_+60.9<br> How do I solve this?

timurjin [86]

Answer:

The answer is <u>54.6</u>.

9.1(6)+8.7(7)=<u>54.6</u>+60.9

Step-by-step explanation:

Given:

9.1(6)+8.7(7)=_+60.9

Now, to solve it:

9.1(6)+8.7(7)=_+60.9

Let the _be x.

So, we remove parenthesis first that makes it multiply with the number next to it:

$9.1\times 6+8.7\times 7=x+60.9$

$54.6+60.9=x+60.9$

Now adding on L.H.S:

$115.5=x+60.9$

Subtracting on both sides by 60.9 we get:

$54.6=x$

$x=54.6$

Therefore, the answer is 54.6.

7 0

3 years ago

Using the order of operations,what should be done first to evaluate 12÷(-6)(3)+(-2)

Maru [420]

Perentheses, probably do multiplication.

4 0

3 years ago

Read 2 more answers

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq

azamat

Answer:

The perimeter of rectangle is $18\ cm$

Step-by-step explanation:

Let

x-----> the length of the rectangle

y----> the width of the rectangle

we know that

$x=y+5$ ----> equation A

$120=xy+2x^{2}+2y^{2}$ ---> equation B (area of the constructed figure)

substitute the equation A in equation B

$120=(y+5)y+2(y+5)^{2}+2y^{2}$

$120=(y+5)y+2(y+5)^{2}+2y^{2}\\ 120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\ 120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\120=5y^{2}+25y+50\\5y^{2}+25y-70=0$

using a graphing calculator -----> solve the quadratic equation

The solution is

$y=2\ cm$

Find the value of x

$x=y+5 ----> x=2+5=7\ cm$

Find the perimeter of rectangle

$P=2(x+y)=2(7+2)=18\ cm$

8 0

2 years ago

34kurt

Answer:

I think it might be B.) Triangle B

Step-by-step explanation:

6 0

3 years ago

Which of the following describes how to translate the graph y = |x| to obtain the graph of y = |x + 7|?

jek_recluse [69]

Answer:

Graph of the function $y=|x+7|$ is translated 7 units to the left graph of the function $y=|x|.$

Step-by-step explanation:

If you are given the function $y=f(x),$ then the graph of the function

$y=f(x-a)$ is translated a units to the right graph of the function $f(x);$
$y=f(x+a)$ is translated a units to the left graph of the function $f(x);$
$y=f(x)+a$ is translated a units up graph of the function $f(x);$
$y=f(x)-a$ is translated a units down graph of the function $f(x).$

In your case, graph of the function $y=|x+7|$ is translated 7 units to the left graph of the function $y=|x|.$

8 0

3 years ago