Question

Will GIVE BRAINLIEST ---A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water.

Answer 1

Answer:

a) 0.5198 mol/L

b) 0.00811 mol KOH

Explanation:

a) M(KOH) = 39+16+1= 56 g/mol

14.555g* 1 mol/56 g = 14.555/56 mol  KOH in 500.0 mL solution

14.555/56 mol  KOH ---- 0.5000 L solution

x mol KOH               ----- 1 L solution

x = (14.555/56)mol * 1L/0.5000 L = 0.5198 mol/L

b) If the student pours out a 15.6 mL sample of this solution, how many moles of sodium hydroxide? (if we talk about KOH)

does the student have in the sample

15.6 mL = 0.0156 L

0.5198 mol/L * 0.0156 L = 0.00811 mol KOH