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pantera1 [17]
3 years ago
7

Why does a tree cast a shadow during the daytime? A. The tree is a source of light for the Earth. B. The tree creates sunlight.

C. The tree blocks light from the Sun. D The tree pulls the light off of the ground.​
Chemistry
1 answer:
Minchanka [31]3 years ago
8 0
The answer is C because uh. It makes sense
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What mass is in 5 moles of helium?
ArbitrLikvidat [17]

Answer:

Mass = 20 g

Explanation:

Given data:

Number of moles of He = 5 mol

Mass of He = ?

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass = 4 g/mol

by putting values,

5 mol = Mass / 4 g/mol

Mass = 5 mol × 4 g/mol

Mass = 20 g

3 0
3 years ago
2. Which electron dot structure represents a nonpolar molecule?
TEA [102]

Answer:

it's d. H:C:C:F

5 0
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What does “like dissolves like” mean?
Tems11 [23]

Answer:

c  solvents dissolve chemicals with the same polarity ( ex. both are polar)

Explanation:

Like dissolves like is one of the central rule that guides the solubility of one substance in another.

  • It fully suggests substance having the same nature as in polarity-wise will dissolve one another.
  • For example, water is a polar liquid, it will dissolve table salt because it i also polar.
  • Water cannot dissolve oil because oil is non-polar.
4 0
3 years ago
If you have a voltage of 120 volts entering your house and a light bulb with 0.625 amperes flowing through it, how many watts is
Luba_88 [7]

Answer:

75 watts

Explanation:

4 0
3 years ago
Read 2 more answers
Determine the resulting pH when 12mL if 0.16M HCl are reacted with 32 mL if 0.24M KOH.
TEA [102]

Answer:

pH = 13.1

Explanation:

Hello there!

In this case, according to the given information, we can set up the following equation:

HCl+KOH\rightarrow KCl+H_2O

Thus, since there is 1:1 mole ratio of HCl to KOH, we can find the reacting moles as follows:

n_{HCl}=0.012L*0.16mol/L=0.00192mol\\\\n_{KOH}=0.032L*0.24mol/L=0.00768mol

Thus, since there are less moles of HCl, we calculate the remaining moles of KOH as follows:

n_{KOH}=0.00768mol-0.00192mol=0.00576mol

And the resulting concentration of KOH and OH ions as this is a strong base:

[KOH]=[OH^-]=\frac{0.00576mol}{0.012L+0.032L}=0.131M

And the resulting pH is:

pH=14+log(0.131)\\\\pH=13.1

Regards!

3 0
3 years ago
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