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hjlf
3 years ago
14

A tree is supported by a wire anchored in the ground 5 feet from its base. The wire is 1 foot longer than the height that it rea

ches on the tree. Find the length of the wire
Mathematics
1 answer:
Agata [3.3K]3 years ago
8 0
A Pythagorean triple with a short side of 5 and other lengths differing by 1 is the triple (5, 12, 13).

The wire is 13 feet long.

_____
If you want to work it out algebraically, you can let x represent the length of the wire. Then the Pythagorean theorem tells you
  x^2 = (x -1)^2 +5^2
  x^2 = x^2 -2x +1 +25
  2x = 26
  x = 13
The length of the wire is 13 feet.
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Baker made 5 pounds of icing. He used 4/9 of the icing to decorate. How much did he have left over?
Elena L [17]
If the baker made 5 pounds of icing and used 4/9 of the icing to make decorations, then he used:

5 * 4/9 =
= 20/9 =
= 2 2/9 [of icing]

To find out how much he has left over, we just need to substract 2 2/9 from 5:

5 - 2 2/9 =
= 3 - 2/9 =
= 2 7/9

Answer: The baker has <u>2 7/9</u> of the icing left.
6 0
3 years ago
Net for a cube has a total surface area of 150 in.2. what is the length of one side of a square face
djverab [1.8K]
Surface area of a cube is given by
SA=6a²
but
SA=150 in²
thus
150=6a²
solving for a we obtain:
150/6=a²
a²=25
thus
a=√25
a=5 inches
hence the side length is 5inches
5 0
3 years ago
Please help me I stink at math ☹️
Greeley [361]
4) Part A draw half of a trapezoid
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3 years ago
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4 0
3 years ago
A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced; then
jarptica [38.1K]

Answer:

\frac{2}{15}

Step-by-step explanation:

GIVEN: A bag contain 5 red marbles,4 green marbles and 1 blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.

TO FIND: What is the probability both marbles are green.

SOLUTION:

Total marbles in bag =10

total number of green marbles =4

Probability that first marble will be green P(A)=\frac{\text{total green marbles}}{\text{total marbles}}

                                                                    =\frac{4}{10}=\frac{2}{5}

Probability that second marble will be green P(B)=\frac{\text{total green marble in bag}}{\text{total marble in bag}}

                                                                                    \frac{3}{9}=\frac{1}{3}

As both events are disjoint

probability both marbles are green =P(A)\times P(B)

                                                           =\frac{2}{5}\times\frac{1}{3}=\frac{2}{15}

Hence  the probability both marbles are green is \frac{2}{15}

8 0
3 years ago
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