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madreJ [45]
3 years ago
10

The _______ is responsible for forming the outer, limiting barrier of a cell.

Biology
1 answer:
Jet001 [13]3 years ago
4 0
The Plasma membrane<span> is responsible for forming the outer, limiting barrier of a cell.</span>
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Which if the following genotypes is heterozygous dominant<br>A. bb<br>B. BBss<br>C. TTSS<br>D. Ss
svp [43]
Heterozygous means that there are two different types of alleles, one dominant and one recessive.
 The correct answer for this answer would be D. Ss because it is one dominant allele and one recessive making it heterozyous

7 0
3 years ago
Can somebody give me the answer for these...
77julia77 [94]

Answer:

1. The set of DNA and RNA sequences that determine the amino acid sequences used in the synthesis of an organism's proteins.

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3.Before a cell divides, its DNA is replicated (duplicated.)

4. A protein is made from amino acids, these form a strand of DNA

5.a mutation is the alteration of the nucleotide sequence of the genome of an organism, virus, or extrachromosomal DNA

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6 0
4 years ago
What is the term for the amount of space occupied by an object?
Arturiano [62]

Answer: volume

Explanation:

7 0
3 years ago
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Stand with your back to a lamp and your hand in front of you. Where does your shadow fall?
BARSIC [14]
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8 0
3 years ago
The Km of your favorite enzyme that operates by normal Michaelis-Menten kinetics is 10-6 M. You start off with a substrate conce
swat32

Answer: (a) 0 no free enzyme left

(b) 10^-9M

Explanation:

ANSWER:

Given that

Kcat = 10 sec-1

Km = 10^-6 M

[S] = 10^-3 M

[Enzyme] = 10^-9 M

The reaction follows the following path-

Enzyme (E) + Substrate (S) <=> ES complex -> E + Product (P)

According to the improved model of Michaelis-Menten kinetics, upon addition of substrate and the enzyme, instead of dynamic equilibrium, a steady state is reached. The time taken is very less, almost instantaneously (since Kcat is much higher than the concentrations we are dealing with (10 per second! Whereas we are dealing with concentrations as low as 10-9).

In this steady state, the Enzyme and substrate instead of existing individually, exist as an Enzyme-Substrate complex, or ES complex.

Physically, Km is a measure of how well substrate complexes with an enzyme, i.e. It's binding affinity.

You can imagine this as if 1 unit of the substrate can bind to "Km" units of Enzyme. For the give conditions, 1 M of the substrate requires 10^-6 M enzyme for complete binding. So, 10^-3 M of the substrate will require 10^-3 x 10^-6 = 10^-9 M of the enzyme, which is the exact amount of enzyme added to the reaction mixture.

So it is safe to assume that when the steady state is reached, all of the enzyme is bound to the available substrate producing the ES complex with the concentration equal to the limiting reactant, i.e. the enzyme = 10^-9 M

Hence, there will be no free enzyme left after the short duration of the reaction. And the concentration of the ES complex will be 10^-9 M

8 0
3 years ago
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