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ch4aika [34]
3 years ago
8

Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in sl

ope-intercept form.
Mathematics
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

y=-0.5x+4.5

Step-by-step explanation:

The slope of y=2x-6 is:

  • 2

The negative reciprocal of that slope is:

  • m=-\frac{1}{2}

So the perpendicular line will have a slope of -1/2:

  • y - y_1 = (-\frac{1}{2} )(x - x_1)

And now put in the point (1,5):

  • y-5=(-\frac{1}{2})(x-1)

And that answer is OK, but let's also put it in y=mx+b form:

  • y-5=-\frac{x}{2}+\frac{1}{2}
  • y=-\frac{x}{2}+\frac{11}{2}
  • y=-0.5x+4.5
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