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2 years ago

8

Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in sl

ope-intercept form.

1 answer:

mr Goodwill [35]2 years ago

8 0

Answer:

$y=-0.5x+4.5$

Step-by-step explanation:

The slope of $y=2x-6$ is:

$2$

The negative reciprocal of that slope is:

$m=-\frac{1}{2}$

So the perpendicular line will have a slope of $-1/2$ :

$y - y_1 = (-\frac{1}{2} )(x - x_1)$

And now put in the point $(1,5)$ :

$y-5=(-\frac{1}{2})(x-1)$

And that answer is OK, but let's also put it in $y=mx+b$ form:

$y-5=-\frac{x}{2}+\frac{1}{2}$
$y=-\frac{x}{2}+\frac{11}{2}$

$y=-0.5x+4.5$

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