Question

Find the equation of the line perpendicular to y=2x-6 that passes through the point (1,5). If possible, write the equation in slope-intercept form.

Answer 1

Answer:

$y=-0.5x+4.5$

Step-by-step explanation:

The slope of $y=2x-6$ is:

• $2$

The negative reciprocal of that slope is:

• $m=-\frac{1}{2}$

So the perpendicular line will have a slope of $-1/2$:

• $y - y_1 = (-\frac{1}{2} )(x - x_1)$

And now put in the point $(1,5)$:

• $y-5=(-\frac{1}{2})(x-1)$

And that answer is OK, but let's also put it in $y=mx+b$ form:

• $y-5=-\frac{x}{2}+\frac{1}{2}$
• $y=-\frac{x}{2}+\frac{11}{2}$

• $y=-0.5x+4.5$