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Ostrovityanka [42]
3 years ago
9

If f(x) = x2 + 1 and g(x) = x - 4, which value is equivalent to (fºg)(10)?

Mathematics
2 answers:
jolli1 [7]3 years ago
6 0

Answer:

2x - 3..... 2*10 - 3 = 17

Step-by-step explanation:

Fog) = g(fx)) = f(x) - 4 => 2x - 3

kari74 [83]3 years ago
6 0

Answer:

37

Step-by-step explanation:

Substitute x = 10 into g(x), then substitute the result into f(x)

g(10) = 10 - 4 = 6 then

f(6) = 6^2 + 1 = 36 + 1 = 37

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7: Jikayla earns $19 per hour babysitting. Last week, she worked 7 hours on Monday, 6 hours on Tuesday, and 7 hours on Wednesday
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Step-by-step explanation:

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4 years ago
You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co
alex41 [277]

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P=2x+2y

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Furthermore, the area of the enclosed land is given by

A=xy

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\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}

To find the maximum possible area, solve A'(y)=0, as shown below

\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}

Therefore, the corresponding value of x is

\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}<h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2>\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}<h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

7 0
1 year ago
Need help asap please​
victus00 [196]

Answer:

z=3.3 repeating

Step-by-step explanation:

Move all terms that don't contain  z  to the right side and solve.

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