Point A is at (12,12)
Point B is at (48,24)
Use the distance formula √((x2-x1)^2 + (y2-y1)^2)
Length = √((48-12)^2 + (24-12)^2)
Length = √(36^2 + 12^2)
Length = √(1296 + 144)
Length = √1440
The answer is E.
an explicit formula for the arithmetic sequence -5,13,31,49 is
.
<u>Step-by-step explanation:</u>
Here we have an arithmetic sequence -5,13,31,49 . We need to find an explicit formula for the arithmetic sequence .Let's find out:
Let
be terms of an A.P , common difference is :
⇒ ![d=a_2-a_1](https://tex.z-dn.net/?f=d%3Da_2-a_1)
⇒ ![d=13-(-5)](https://tex.z-dn.net/?f=d%3D13-%28-5%29)
⇒ ![d=13+5](https://tex.z-dn.net/?f=d%3D13%2B5)
⇒ ![d=18](https://tex.z-dn.net/?f=d%3D18)
We know that general term of an Arithmetic Progression ( A.P) is :
⇒ ![a_n = a+(n-1)d](https://tex.z-dn.net/?f=a_n%20%3D%20a%2B%28n-1%29d)
So , Here we will have ![a_n = -5+(n-1)18](https://tex.z-dn.net/?f=a_n%20%3D%20-5%2B%28n-1%2918)
⇒ ![a_n = -5+(n-1)18](https://tex.z-dn.net/?f=a_n%20%3D%20-5%2B%28n-1%2918)
⇒ ![a_n = -5+18n-18](https://tex.z-dn.net/?f=a_n%20%3D%20-5%2B18n-18)
⇒ ![a_n =18n-23](https://tex.z-dn.net/?f=a_n%20%3D18n-23)
Therefore , an explicit formula for the arithmetic sequence -5,13,31,49 is
.
Decrease = New number - Original Number
% Decrease =
![\frac{Decrease}{Original~number}](https://tex.z-dn.net/?f=%20%5Cfrac%7BDecrease%7D%7BOriginal~number%7D%20)
× 100
Decrease = 9 - 12 = -3
% Decrease =
![\frac{-3}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B-3%7D%7B12%7D%20)
= -0.25 × 100 = -25
Your answer =
-25
Answer:
can i see a pic
Step-by-step explanation: