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Evgen [1.6K]
4 years ago
13

Sue wants to plan a meal with 71 grams of fat and 1755 calories. If hot dogs have 13 grams of fat and 145 calories each and if b

aked beans have 8 grams of fat and 330 calories per half-cup serving, how many hot dogs and servings of beans should she use?
Mathematics
1 answer:
Lena [83]4 years ago
4 0

Answer:

Sue must use 3 hotdogs and 4 half-cup serving of baked beans.

Step-by-step explanation:

Let the number of hot dogs be represented by h

Let the number of baked beans be represented by b

Hot dogs have 13 grams of fat and 145 calories each

Baked beans have 8 grams of fat and 330 calories per half cup serving

Sue wants to plan a meal with 71 grams of fat and 1755 calories.

Grams of Fat from Hotdog + grams of fat from baked beans=71

13h+8b=71....(I)

Similarly,

Calories from hot dog + Calories from baked beans=1755

145h+330b=1755....(II)

We then solve Equations (I) and (II) simultaneously.

13h+8b=71....(I)

145h+330b=1755....(II)

Multiply equation 1 by 145 and equation 2 by 13

1885h+1160b=10295

1885h+4290b=22815

Subtracting

-3130b=-12520

b=4

Substitute b=4 into (I)

13h+(8X4)=71

13h=71-32

13h=39

h=3

Sue must use 3 hotdogs and 4 half-cup serving of baked beans.

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Oksana_A [137]

Answer: the integers are 6 and 23

Step-by-step explanation:

Let x represent one of the integers.

Let y represent the other integer.

The product of the integers is 138. This means that

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One of the integers is seven less than five times the other integer. This means that

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Substituting x = 5y - 7 into equation 1, it becomes

y(5y - 7) = 138

5y² - 7y = 138

5y² - 7y - 138 = 0

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y(5y + 23) - 6(5y + 23)

y - 6 = 0 or 5y + 23 = 0

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The only possible value of y is 6

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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