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vladimir1956 [14]
3 years ago
10

I need help on question #1 asap

Mathematics
2 answers:
Liula [17]3 years ago
7 0
3 arrangements are possible. Have a nice day! ^ U ^
bekas [8.4K]3 years ago
3 0
The answer is three. divide 48 by any number under 6 if there a decimal they don't count if there answer is over 20 it doesn't count
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License plates are made using 3 letters followed by 2 digits. How many plates can be made if repetition of letters and digits is
Helga [31]

Answer:

26^3\times10^2 = 1757600

option B is correct

Step-by-step explanation:

We have 5 spaces in the license plate:

_ _ _ _ _

we have 26 available letters, and 10 available numbers.

starting with letters:

  • how many choices do i have to place the 1st letter? 26.

26 _ _ _ _

  • how many choices do i have to place the 2nd letter? 26 (since we're allowed to repeat letters)

26 26 _ _ _

  • how many choices do i have to place the 3rd letter? 26

26 26 26 _ _

we've used all the places for letters, (note: the exact position of the letters doesn't matter here, the first letter could've been placed anywhere in _ _ _ _ _, but the amount of possible choices for letters would always be 26).

let's move on to numbers.

  • how many choices do i have to place the 1st number? 10

26 26 26 10 _

  • how many choices do i have to place the 2nd number? 10

26 26 26 10 10

we've completed our number plate. Next we'll simply multiply all these numbers to get all the possible arrangements in which numbers and letters can be displayed on a license place.

26^3\times10^2 = 1757600

option B is correct

8 0
3 years ago
Solve the following inequality.<br> -4(1 - 5a) &gt; -124
NemiM [27]

Answer:

a>−6

Step-by-step explanation:

−4(1−5a)>−124

Step 1: Simplify both sides of the inequality.

20a−4>−124

Step 2: Add 4 to both sides.

20a−4+4>−124+4

20a>−120

Step 3: Divide both sides by 20.

20a/20> −120/20

a>−6

8 0
2 years ago
What is the greatest common factor of 73 and 30
sergij07 [2.7K]

Answer:1

Step-by-step explanation:

they have no other common factors

4 0
3 years ago
Read 2 more answers
How do I search up friends here?
navik [9.2K]

Answer:

I don't think you can..

Step-by-step explanation:

8 0
3 years ago
About Exercise 2.3.1: Proving conditional statements by contrapositive Prove each statement by contrapositive
Sladkaya [172]

Answer:

See proofs below

Step-by-step explanation:

A proof by counterpositive consists on assuming the negation of the conclusion and proving the negation of the hypothesis.

a) Assume that n is not odd. Then n is even, that is, n=2k for some integer k. Hence n²=4k²=2(2k²)=2t for some integer t=2k². Then n² is even, therefore n² is not odd. We have proved the counterpositive of this statement.

b) Assume that n is not even, then n is odd. Thus, n=2k+1 for some integer k. Now, n³=(2k+1)³=8k³+6k²+6k+1=2(4k³+3k²+3k)+1=2t+1 for the integer t=4k³+3k²+3k. Thus n³ is odd, that is, n³ is not even.

c) Suppose that n is not odd, that is, n is even. Now, n=2k for some integer k. Then 5n+3=10k+3=2(5k+1)+1, thus 5n+3 is odd, then 5n+3 is not even.

d) Suppose that n is not odd, then n is even. Now, n=2k for some integer k. Then n²-2n+7=4k²-4k+7=2(2k²-2k+3)+1. Hence n²-2n+7 is odd, that is, n²-2n+7 is not even.

e) Assume that -r is not irrational, then -r is rational. Since -1 is rational, then (-1)(-r)=r is rational. Thus r is not irrational.

f) Assume that 1/z is not irrational. Then 1/z is rational. Multiplucative inverses of rational numbers are rational, hence z is rational, that is, z is not irrational.

g) Suppose that z>y. We will prove that z³+zy²≤z²y+y³ is false, that is, we will prove that z³+zy²>z²y+y³. Multiply by the nonnegative number z² in the inequality z>y to get z³>z²y (here we assume z and y nonzero, in this case either z³>0=y³ is true or z³=0>y³ is true). On the other hand, multiply by z² (positive number) to get zy²>y³. Add both inequalities to obtain z³+zy²>z²y+y³ as required.

h) Suppose than n is even. Then n=2k, and n²=4k² is divisible by 4.

i) Assume that "z is irrational or y is irrational" is false. Then z is rational and y is rational. Rational numbers are closed under sum, then z+y is rational, that is, z+y is not irrational.

3 0
3 years ago
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