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3 years ago

The length of a rectangle is 6m more then the width. The area is 40m^2 . What is the length and the width?

Mathematics

1 answer:

erastova [34]3 years ago

4 0

let the width of the rectangle be x

area of rectangle is l*b

x * (x + 6) = 40^2

x^2 + 6x = 40^2

x^2 + 6x = 1600

x + 6x =√1600

x + 6x = 40

7x = 40

x = 5.7

Hope you found this useful

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2 years ago

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2 years ago

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(a) P-value = 0.074, α = 0.05 do not reject H0

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Step-by-step explanation:

The p-value is used to determine the statistical significance of the results of a statistical test. The p-value is the probability that the null hypothesis is correct. Smaller the p-value, higher is the probability that the alternate hypothesis is correct. On the other hand, the significance level (α) is the probability of rejecting the null hypothesis when it is true. It is the risk that you are willing to take in saying that there are differences between groups when there are not.

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3 years ago

The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri

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Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ $AD^{2} + BD^{2} = AB^{2}$