In the recursive formula an = an−1 + 5, the value of the previous term is represented by

Mathematics

1 answer:

den301095 [7]3 years ago

6 0

Step-by-step explanation:

In the recursive formula an = an−1 + 5

$a_n = a_{n-1}+5$

Suppose if a_5 is the nth term then previous term is a_4

To get the previous term we need to subtract 1 from the n

So a_n is the nth term

$a_{n-1}$ is the previous term

Here 5 represents the common difference between two terms

So value of previous term is represented by

$a_{n-1}$

Answer : $a_{n-1}$

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How do measurements of time differ for events in a frame of reference that moves at 50% of the speed of light relative to us? At

ZanzabumX [31]

Answer with explanation:

Relation between Speed , Distance and time

Distance =Speed × Time

→It means Speed is inversely Proportional to time.

As distance will remain constant , in that frame of reference

If speed of light in a Medium

$=s=3 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = t seconds or hours or another unit of time.

Now, If speed of light is 50% of the speed of light relative to us

That is Speed of light in another medium

$=w=\frac{50}{100} \times 3 \times 10^8\\\\=1.5 \times 10^8 \frac{\text{meter}}{\text{second}}$

Then, time taken to cross the medium = 2t seconds or hours or another unit of time.

Using Unitary Method

$\rightarrow v_{1}\times t_{1}=v_{2} \times t_{2}\\\\1.\rightarrow 3 \times 10^8 \times t=\frac{50}{100} \times 3 \times 10^8 \times t_{1}\\\\t_{1}=2t\\\\2.\rightarrow 3 \times 10^8 \times t=\frac{99.5}{100} \times 3 \times 10^8 \times t_{2}\\\\t_{2}=\frac{1000t}{995}\\\\t_{2}=\frac{200t}{199}$