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Andrews [41]
3 years ago
10

Given right triangle DEF, what is the value of sin(E)? A. 3/5 B. 3/4 C. 4/5 D. 4/3

Mathematics
2 answers:
wariber [46]3 years ago
8 0

Answer: OPTION A.

Step-by-step explanation:

First you must calculate the lenght of the side DF by applying the Pythagorean theorem, as following:

DE=\sqrt{10^{2}-8^{2}}=6

Now you can find sin(E) as you can see below:

sin\alpha=opposite/hypotenuse

Where:

\alpha=E\\opposite=DF=6\\hypotenuse=EF=10

Then:

 sin(E)=6/10

sin(E)=3/5

xenn [34]3 years ago
6 0

Answer:

The correct answer is option A. 3/5

Step-by-step explanation:

<u>Pythagorean theorem:-</u>

Hypotenuse² = Base² + Height²

Trigonometric ratio:-

Sin(∅) = Opposite side / Hypotenuse

It is given a right angled triangle DEF.

DE = 8 and FE = 10

<u>To find the length of DF</u>

Hypotenuse² = Base² + Height²

FE² = DF² + DE²

DF² = FE² - DE² =  10² - 8² = 100 - 64 = 36

DF =√36 = 6

<u>To find Sin(E)</u>

Sin(E) = Opposite side / Hypotenuse = DF/EF = 6/10 =3/5

Sin(E) = 3/5

The correct answer is option A. 3/5

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3 years ago
Factorise 12x² + x - 20​
swat32

━━━━━━━☆☆━━━━━━━

▹ Answer

<em>(3x + 4) * (4x - 5)</em>

▹ Step-by-Step Explanation

12x² + x - 20

<u>Rewrite </u>

12x² + 16x - 15x - 20

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