What is the ration of 8 lions and 4 tigers

Can someone help me please!!!!

Softa [21]

Answer:

step 1. DBE ~ ABC

step 2. (x + 5)/4 = (2x + x + 5)/(4 + 3)

step 3. ( x + 5)/4 = (3x + 5)/7

step 4. 7x + 35 = 12x + 20

step 5. 5x = 15

step 6. x = 3.

6 0

2 years ago

In triangle ABC, the measure of angle B is 44 degrees more than three times the measure of angle A. The measure of angle C is 61

lianna [129]

Answer:

m∠A = 15°; m∠B = 89°; m∠C = 76°

Step-by-step explanation:

The sum of the three interior angles of a triangle is 180°.

Let x = m∠A

Then 3x + 44 = m∠B

and x + 61 = m∠C

x + 3x + 44 + x + 61 = 180

5x + 105 = 180

5x = 75

x = 15

m∠A = 15°

m∠B = 3(15) + 44 = 45 + 44 = 89°

m∠C = 15 + 61 = <u> 76°</u>

Sum = 180°

7 0

2 years ago

HELP PLS

jeka94

There is no correlation. We know this because it doesn’t matter how many samples were provided, the customers still bought approximately the same number of bottles.

4 0

2 years ago

One fifth of Bill's age is 4 years. Find Bill's age.

dimulka [17.4K]

The answer is A). 5*4=20 one fifth is 4.

7 0

3 years ago

An icicle with a diameter of 15.5 centimeters at the top, tapers down in the shape of a cone with a length of

Helga [31]

Answer:

Step-by-step explanation:

Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.

From the question, we can tell it is a inversed-cone (upside down)

Volume of Cone = $\pi r^{2} \frac{h}{3}$

a) Given Diameter , d = 15.5cm and Length , h = 350cm,

we first find the radius.

$r = \frac{d}{2} \\=\frac{15.5}{2} \\=7.75cm$

We will now find the volume of the cone.

Volume of cone $\pi (7.75)^{2} \frac{350}{3} \\= \frac{168175\pi }{24}$

We know the density of ice is 0.93 grams per $1cm^{3}$

$1cm^{3} =0.93g\\\frac{168175\pi }{24} cm^{3} =0.93(\frac{168175\pi }{24} )\\= 20473 g$ (Nearest Gram)

b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm

and the new length, h = 350cm - 15cm = 335cm

Now we will find the volume of this newly-shaped cone.

Volume of cone = $\pi (7.4)^{2} \frac{335}{3} \\= \frac{91723\pi }{15} cm^{3}$

Volume of cone being melted = New Volume - Original volume

= $\frac{168175\pi }{24} -\frac{91723\pi }{15} \\= \frac{35697\pi }{40} cm^{3}$

c) Lets take the bucket as a round cylinder.

Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.

Volume of cylinder = $\pi r^{2} h\\=\pi (12.5)^{2} (30)\\=\frac{9375\pi }{2} cm^{3}$

To overflow the bucket, the volume of ice melted must be more than the bucket volume.

Volume of ice melted after 5 hours = $5(\frac{35697\pi }{40} )\\=\frac{35697\pi }{8} cm^{3}$

See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.

Volume of bucket - Volume of ice melted after 5 hours

= $\frac{9375\pi }{2} -\frac{35697\pi }{8 } \\=\frac{1803\pi }{8}cm^{3}$

from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.

4 0

1 year ago