To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
I think maybe A Im not 100% sure tho
Ohh well when u type in another question it should show a pic option at the bottom once your done typing whatever is u wish to ask :)
4 Triangles 1/2(6)6()= 18 18x4= 72
5 squares 3X3=9. 5x9= 45
72+45= 117 sq in
