Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
Exact Form:
x
=
64/21e
Decimal Form:
x
=
1.12115639
Step-by-step explanation:
Answer:
The answer to your question is x = 6
Step-by-step explanation:
Equation 5x + 3x - 6 = 42
Process
Step 1. Add 6 units in both sides
5x + 3x - 6 + 6 = 42 + 6
Step 2. Simplify
5x + 3x = 48
Step 3. Simplify like terms
8x = 48
Step 4. Divide by 8 both sides
8x/8 = 48/8
Step 5. Simplify
x = 6
Answer: helllloooooooooooooo000000oooo
Step-by-step explanation: