Y = -4/3x + 5....the slope here is -4/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, flip the original slope and change the sign. So we have -4/3....we flip it and it becomes - 3/4....we change the sign and it becomes 3/4. So the perpendicular line will have a slope of 3/4.
y = mx + b slope(m) = 3/4 (5,-4)...x = 5 and y = -4 now we sub into the formula and find b, the y int -4 = 3/4(5) + b -4 = 15/4 + b -4 - 15/4 = b -16/4 - 15/4 = b -31/4 = b so ur perpendicular equation is : y = 3/4x + (-31/4) which is written as : y = 3/4x - 13/4 <== ur answer
As this line is <span>perpendicular to the line y=-4/3x+5 , so it has une equation: y=3/4x+b, b is unknown. ( you know that a*a'=-1) IN addition, this line pass through the point (5;-4) and we have x=5 and y=-4 so, -4=3/4 x 5 +b and b=-4-15/4=-31/4 And we have y=3/4x-31/4 Have fun </span>