How many quarters can you get for a five dollar bill

1 answer:

4 0

You can get 20 quarters for a five dollar bill. Just divide 5.00 by 0.25 and you get 20. To check, you can multiply 20 by 0.25 and you will get 5.00 or 5.

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Why can't a trapezoid have 4 obtuse angles

In-s [12.5K]

Hello there, and thank you for posting your question here on brainly.

A trapezoid is not possible to have for obtuse because it would look more like a diamond. Also, if it had 4 obtuse angles, it would have 6 sides.

Hope this helped!! ☺♥

7 0

3 years ago

Read 2 more answers

(HELP!)which statement about numbers is true?

marusya05 [52]

Answer:

All natural numbers are whole numbers because in the numbers diagram natural numbers are within whole numbers

Step-by-step explanation:

8 0

3 years ago

* Required

Furkat [3]

B. 19.8

Use the Pythagorean theorem:
14.2^ + x^ = 24.4^
201.64 + x^ = 595.36
x^ = 393.72
x = 19.84

8 0

3 years ago

Which function has an inverse that is also a function? Group of answer choices g ( x ) = 2 x − 3 w ( x ) = − 20 k ( x ) = 9 x 2

wlad13 [49]

Answer:

what's nine plus ten= "twenty-one" you stoopid "no i'm not"

Step-by-step explanation:

8 0

3 years ago

Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"

dsp73

For any scalars $c_1,c_2$ , we have

$c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w$

So

$\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w$

We have

$\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}$
$=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k$
$=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k$
$=\begin{bmatrix}-60\\9\\76\end{bmatrix}$

which makes

$\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}$

4 0

3 years ago