3 years ago

QF Q2.) Solve the triangle.

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

6 0

See photo for soln and answer

Marianna [84]3 years ago

5 0

C=180-A-B=180-67-53=60deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=13/sin(67)*sin(53)
= 11.28

c/sinC=a/sinA
c=a/sinA*sinC
=13/sin(67)*sin(60)
= 12.23

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