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3 years ago

6

on a map, the distance between jacksonville FL and tallahasse FL is about 5 inches. According to the scale, 1 inch represents 25

miles. About how far apart are these two cities?

1 answer:

Sergio [31]3 years ago

8 0

Jacksonville Fl and Tallahassee FL will be about 125 miles apart in real life.

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Please help me with this!!!

krok68 [10]

Answer:

the answer is A because if it is raised to the power greater than one and is added it will be greater than1

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3 years ago

Give three real-world examples of rectangular prisms. Then give two real-world examples of triangular prisms. Explain how you kn

denpristay [2]

Three real world examples of rectangular prisms include juice boxes, cereal boxes, and even cargo containers. Two real world examples of triangular prisms include camping tents and triangular roofs. I chose these objects to represent triangular and rectangular prisms because triangular prisms have two triangular faces and three rectangular faces and rectangular prisms have six rectangular faces.

Sample Response: Boxes, ice cubes, and brick are examples of rectangular prisms. Ramps and tents are examples of triangular prisms. A rectangular prism has six rectangular faces. A triangular prism has two triangular faces and three rectangular faces.

3 0

3 years ago

Read 2 more answers

Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p

Ymorist [56]

Answer:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

$A\sim Uniform(1 ,7)$

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

$B\sim Exp(\lambda=\frac{1}{30 min})$

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

$E(A +B)$

Since the two random variables are assumed independent, then we have this

$E(A+B) = E(A)+E(B)$

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by $E(X) =\frac{a+b}{2}$ where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

$E(A)=\frac{1+7}{2}=4 hours$

The expected value for the exponential distirbution is given by :

$E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx$

If we use the substitution $y=\lambda x$ we have this:

$E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}$

Where X represent the random variable and $\lambda$ the parameter. If we apply this formula to our case we got:

$E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min$

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

$E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours$

And in order to find the variance for the random variable A+B we can find the individual variances:

$Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2$

$Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2$

We have the following property:

$Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)$

Since we have independnet variable the Cov(A,B)=0, so then:

$Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2$

3 0

4 years ago

What is the slope of a line that passes through the points (-2, 4) and (-6, 12)?

irga5000 [103]

Answer:

C is your answer for this question

8 0

3 years ago

What is the measure is the angle shown with the question mark?

Ilya [14]

The interior angles of a quadrilateral( 4 sided figure) add up to 360 degrees.

114 + 84 + 94 + x = 360
292 + x = 360
x = 360 - 292
x = 68 <== ur missing angle

5 0

3 years ago

Read 2 more answers