Pretty good so far its hard also.
Answer:
1 foot long
Step-by-step explanation:
If this fraction is closer to one it will be close to 16/16. And since 8 is half of 16, any fraction that is around 8/16 is closer to 1/2. 15 is closer 16 so this fraction is closer to one.
3m-9=9+3m
add 9 to both sides
3m=18+3m
minus 3m both sides
0=18
false
no solution
the best discription would be an empty solution set
<span>The student apparently added numbers without taking into account direction. They seem to have added 15 and 25 and divided by 2 to get the horizontal component of the middle stop when they should have added 15 and -25 and divided by 2. A similar mistake was made on determining the vertical component. The middle stop should have been calculated as 5 blocks west and 7 blocks south of the central station. So your answer is C.</span>
Following transformations on Triangle ABC will result in the Triangle A'B'C'
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
In Triangle ABC, the coordinates of the vertices are:
A (1,9)
B (3, 12)
C (4, 4)
In Triangle A'B'C, the coordinates of the vertices are:
A' (3, -3)
B' (5, -6)
C' (6, 2)
First consider point A of Triangle ABC.
Coordinate of A are (1, 9). If we reflect it across x-axis the coordinate of new point will be (1, -9). Moving it 2 units to right will result in the point (3, -9). Moving it 6 units up will result in the point (3,-3) which are the coordinates of point A'.
Coordinates of B are (3,12). Reflecting it across x-axis, we get the new point (3, -12). Moving 2 units towards right, the point is translated to (5, -12). Moving 6 units up we get the point (5, -6), which are the coordinate of B'.
The same way C is translated to C'.
Thus the set of transformations applied on ABC to get A'B'C' are:
a) Reflection the triangle across x-axis
b) Shift towards Right by 2 units
c) Shift upwards by 6 units
