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evablogger [386]
3 years ago
10

Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!!!

Mathematics
2 answers:
Drupady [299]3 years ago
5 0

Answer:

6

Step-by-step explanation:

f(6) = -6   this is the value when the x value is 6

g(5) = -5 this is the value when the x value is 5

4 * f(6) -6*g(5)

4*-6 - 6* -5

-24 + 30

6

uysha [10]3 years ago
4 0

Answer:

6

_____________________

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snow_lady [41]
A= pi x r^2 x h
so pi x 16 x5

A= 80 pi or 251.3
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3 years ago
14 less than the quotient of 63 and a number h
Monica [59]
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Solve for A ? <br><br> Anyone willing to help me :)
GrogVix [38]

Answer:

<h2>2.2</h2>

Step-by-step explanation:

Use the cosine law:

BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)

We have:

BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848

Substitute:

a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2

5 0
2 years ago
In this swimming pool design, explain how to find the area of the pool's surface. ​
Svetllana [295]
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8 0
2 years ago
Select the two values of x that are roots of this equation.
makkiz [27]

Answer:

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A quadratic equation is given to us.
  • The equation is 2x² + 7x +6=0

And we need to find out the roots of the given equation. We can use the middle term splitting method to find out the roots as ,

<u>Given </u><u>equation</u><u> </u><u>:</u><u>-</u>

\implies 2x^2 + 7x +6=0

Step 1: <u>Find</u><u> out</u><u> the</u><u> </u><u>factors</u><u> </u><u>of </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

We will choose the two factors such that their sum equals to the coefficient of x i.e. 7 .The factors are , 1×12 , 2×6 , 3×4 .

  • And 3 + 4 = 7. So we will break the middle term into 3x and 4x .

Step 2 :<u> Breaking</u><u> the</u><u> </u><u>middle</u><u> term</u><u> </u><u>:</u><u>-</u><u> </u>

\implies 2x^2 + 3x+4x +6=0

Step 3: <u>Take </u><u>out </u><u>common</u><u> </u><u>from </u><u>terms </u><u>:</u><u>-</u>

\implies x(2x + 3) +2(2x +3)=0

\implies ( x +2)(2x+3)=0

Step 4 : <u>Equate </u><u>them </u><u>with </u><u>0</u><u> </u><u>:</u><u>-</u><u> </u>

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

<u>Hence </u><u>the</u><u> </u><u>correct</u><u> </u><u>options </u><u>are </u><u>C </u><u>and </u><u>D </u><u>.</u>

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2 years ago
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