Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
Answer: If there is a drawing then try copy that exact drawing but move it 2 units or squares down and 3 units or squares to the left
Step-by-step explanation:
You could add two until you get to 512
Step-by-step explanation:
x⁴ − 5x³ + 11x² − 25x + 30
x⁴ − 5x³ + 6x² + 5x² − 25x + 30
x² (x² − 5x + 6) + 5 (x² − 5x + 6)
(x² + 5) (x² − 5x + 6)
(x² + 5) (x − 2) (x −3)
The zeros are 2, 3, and ±√5i.
Answer:
m = -2
Step-by-step explanation:
to find the answer you must put rise over run
rise is (y2 - y1) and run is (x2 - x1)
lets use the bottom two points for thisd
y2 is 0 and y1 is 2
x2 is 1 and x1 is 0
0 - 2 = -2
1 - 0 = 1
-2/1 = -2
that is the slope
