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Sindrei [870]
3 years ago
7

I just need an answer please ! ! !

Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

x > -3

y < 2

Pretty much this is saying that any point that meats the specifications of "greater than x=-3 and less then y=2" will be in the colored area.

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How do I start this problem? I don't need help with the graphing part.
tamaranim1 [39]

Answer:

x = 6 , y = 0   (x , y) = (6 , 0)

x = 12, y = 3   (x , y) = (12 , 3)

x = 24, y = 9   (x , y) = (24 , 9)

Step-by-step explanation:

Simply plug in a x, and find a y that would make the equation true:

When x = 6:

6 - 2y = 6

6 (-6) - 2y = 6 (-6)

-2y = 0

(-2y)/-2 = (0)/-2

y = 0

When x = 6, y = 0    (x , y) = (6 , 0)

When x = 12:

12 - 2y = 6

12 (-12) -2y = 6 (-12)

-2y = -6

(-2y)/-2 = (-6)/-2

y = 3

When x = 12, y = 3   (x , y) = (12 , 3)

When x = 24:

24 - 2y = 6

24 (-24) - 2y = 6 (-24)

-2y = -18

(-2y)/-2 = (-18)/-2

y = 9

When x = 24, y = 9   (x , y) = (24 , 9)

~

3 0
3 years ago
2.) (-24)² =<br> How do I simplify the expression using the exponents
Orlov [11]

Answer:

use (-12)^4

Step-by-step explanation:

5 0
3 years ago
Can someone answer this question please answer it correctly if it’s correct I will mark you brainliest
marysya [2.9K]

0.17 , 2/9, 1/4

a= 0.17

b= 2/9

c=1/4

5 0
3 years ago
Read 2 more answers
If f(x) = 1 - 2x^3, find the inverse of f.
Artyom0805 [142]
Swap x and y's positions

f(x) is another way of saying y, so basically tha initial function is y = 1-2x^3.

Change it up to x = 1-2y^3 and solve for y

X - 1 = - 2y^3

(X - 1)/-2 = y^3

So the cube root of ((x-1)/2) = y
7 0
3 years ago
Solve 5h + 2(11 - h) = -5 (Find h. Explain each step please.)
pav-90 [236]

Answer:

h = -9

Step-by-step explanation:

Distribute the 2 to the parentheses:

5h + 2(11 - h) = -5

5h + 22 - 2h = -5

Add like terms:

3h + 22 = -5

3h = -27

h = -9

7 0
3 years ago
Read 2 more answers
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