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garik1379 [7]
4 years ago
7

A bag contains 20 white marbles and 30 black marbles. if 7 marbles are chosen, what is the probability that there will be 2 whit

e marbles and 5 black marbles?
Mathematics
1 answer:
AlekseyPX4 years ago
8 0
This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20)  and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.

Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710

Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710 
as before.
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Step-by-step explanation:

First, we should focus on their records and percents.

Shaka: 30%, -15 points.

Ajani: 40% +35 points.

When we subtract 35 and -15, we get the difference of 50.

We know 10% is 50 point difference, 20% is 100 point difference, 30% is 150 point difference, etc.

But that's not correct.

  • It has to be in the Negatives.
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Since 30% is -15 points, we subtract 50 for 20%, then another 50 for 10%.

Our Correct work is:

0% = -0, 10% = -115, 20% = -65, (30% = -15, 40% = 35.)

- We are correct.

Then, since we are correct, we keep going.

30% = -15, 40% = 35, 50% = 85, 60% = 135, 70% = 185, 80% = 235, 90% = 285, 100% (Or Maximum Point): 335.

Therefore, the Maximum Point is 335 points.

Best of Luck to you!

If you have any questions, feel free to comment below.

Merry Christmas and have a Happy New Year!

Thank You!

Read more on Brainly.com - brainly.com/question/14270303#readmore

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