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3 years ago

7

Question 20 please thank hou

1 answer:

Mekhanik [1.2K]3 years ago

8 0

$\dfrac{9mn-6m}{25-m^2}\div\dfrac{12mn}{5+m}=\dfrac{3m(3n-2)}{5^2-m^2}\cdot\dfrac{5+m}{3m\cdot4n}\\\\=\dfrac{3n-2}{(5-m)(5+m)}\cdot\dfrac{5+m}{4n}=\dfrac{3n-2}{4n(5-m)}\to\boxed{C.}$

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Evaluate the spherical coordinate integral

expeople1 [14]

Rewrite the equations of the given boundary lines:

<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1

<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4

<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2

<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5

This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.

Compute the Jacobian determinant for this change of coordinates:

$J=\begin{bmatrix}\frac{\partial u}{\partial x}&\frac{\partial u}{\partial y}\\\frac{\partial v}{\partial x}&\frac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}1&1\\-2&1\end{bmatrix}\implies|\det J|=3$

Rewrite the integrand:

$-3x+4y=-3\cdot\dfrac{u-v}3+4\cdot\dfrac{2u+v}3=\dfrac{5u+7v}3$

The integral is then

$\displaystyle\iint_R(-3x+4y)\,\mathrm dx\,\mathrm dy=3\iint_{R'}\frac{5u+7v}3\,\mathrm du\,\mathrm dv=\int_2^5\int_1^45u+7v\,\mathrm du\,\mathrm dv=\boxed{333}$

5 0

3 years ago

PLS HELP I'LL MARK BRAINLEST

Andru [333]

Answer: x=55

Step-by-step explanation: 35+35=70. 180-70=110. 110/2=55.

6 0

3 years ago

Read 2 more answers

Please need help on this question

11Alexandr11 [23.1K]

Answer:

..

Step-by-step explanation:

5 0

2 years ago

The solution set for the equation x - 6x + 10 = 0 is

Oxana [17]

Answer:

{3-i, 3+ i}

Step-by-step explanation:

hello : the equation is : x²-6x+10 =0

because : (3+i)²-6(3+i)+10 = 9+6i+i²-18-6i+10 =9+6i-1-18-6i+10 =0...right

same method for 3-i... (all quadratic equation have two conjugate solution)

8 0

3 years ago

Help please with this math ;-; I beg of you

RSB [31]

Answer:

49 - 9π

Step-by-step explanation:

Area of white portion = area of triangle - area of circle

To find the area of the triangle:

The area of a triangle can be calculated using this formula

$A=\frac{bh}{2}$ where b = base length and h = height

The height given is 7m and the base length given is 14m

That being said we plug in the given values into the formula

$\frac{14*7}{2} \\14*7=98\\\frac{98}{2} =49$

Hence, the area of the triangle is 49 sq meters.

To find the area of circle

( note that the area is in terms of pi; shown by the answer choices. )

Formula for area of a circle = $A=\pi r^2$

We are given the diameter ( 6m )

However, we need the radius

To convert diameter to radius we divide by 2

6/2 = 3 so the radius = 3m

Now we plug in 3 into the formula

$A=\pi 3^2\\3^2=9\\A=9\pi$

Remember we do not apply pi because the answer should be in terms of pi.

Now we subtract the two

Area of white portion = 49 - 9π

Hence, the answer is A

7 0

3 years ago

Read 2 more answers