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Sloan [31]
2 years ago
10

PLS HELP I'LL MARK BRAINLEST

Mathematics
2 answers:
Andru [333]2 years ago
6 0

Answer: x=55

Step-by-step explanation: 35+35=70. 180-70=110. 110/2=55.

butalik [34]2 years ago
4 0
X = 55 is the answer hoped it helped :)
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I need help asap someone please help me i dont understand this question so can someone help me
eduard

Answer:

we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

Step-by-step explanation:

Given the expression

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{2p}{4p^2-1}\times \frac{6p+3}{6p^3}

=\frac{2p}{4p^2-1}\times \frac{2p+1}{2p^3}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{2p\left(2p+1\right)}{\left(4p^2-1\right)\times \:2p^3}

cancel the common factor: 2

=\frac{p\left(2p+1\right)}{\left(4p^2-1\right)p^3}

cancel the common factor: p

=\frac{2p+1}{p^2\left(4p^2-1\right)}

=\frac{2p+1}{p^2\left(2p+1\right)\left(2p-1\right)}

cancel the common factor: 2p+1

=\frac{1}{p^2\left(2p-1\right)}

Expanding

=\frac{1}{2p^3-p^2}

Thus, we conclude that:

\frac{2p}{4p^2-1}\div \frac{6p^3}{6p+3}=\frac{1}{2p^3-p^2}

7 0
3 years ago
Someone please help me
ludmilkaskok [199]
Volume=s to the third power
2 1/2 to the third power is 15.625 inches
The answer is 15.625 inches
3 0
2 years ago
I need help with this question ASAP!
mote1985 [20]
The answer is c because 3/6 simplified is equal to 1/2
4 0
2 years ago
How do you write the following linear equations in standard form ?
ANTONII [103]
Hi<span>, Victoriasoto93p63zva!

To rewrite these equations in standard form you need to understand that standard form looks something like this Ax+By=C, now obviously there will be variations like </span>Ax-By=C or -Ax+By=C, etc..., but for these expressions, they would look like this:
<span>1. -8y + 0x = 37
2. 14x </span>+ 4y<span> = -18
3. x + </span>\frac{3}{5} y = \frac{4}{5} <span>
4. 13x + 0y = -25

-</span><span>ASIAX</span><span> </span><span>Frequent Answerer</span>
4 0
2 years ago
Expanding log functions<br> ㏒3 (3(x+1)(x+2))
Oksanka [162]
Log(ab)=log(a)+log(b)
log_a(a)=1
so

log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=1+log_3(x+1)+log_3(x+2)
6 0
3 years ago
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