Answer:
Neurological signals sent from fear responses in an organism tell the cell to stop. The cell's DNA has been damaged somehow. The cell's DNA was replicated incorrectly.
Explanation:
All the three options given can cause checkpoint genes to interrupt cell division.
Checkpoint genes are transcription genes that control cell cycle and sense defects during cells processes like DNA replication, segregation e.t.c and create response till the defects is repaired in the DNA. The important of checkpoint is that it ensure enough nutrients are available to support for division, ensure that the DNA has not been damaged, ensure that cells DNA is copied correctly and make sure cells have enough RNA for their protein synthesis.
Checkpoints genes can interrupt cell division if the dna is damaged, Dna is copied incorrectly and neurological signal sent from fear responses in an organisms tell the cells to stop.
The information is not available regrading the question and its option. The answer will consider the general points regarding the REM sleep in infants.
Answer:
Rapid eye movement (REM) sleep is the sleep that involves the rapid and random movement of the eyes. The muscle tone gets low during the REM sleep. This sleep is present in both infants and adults.
The baby start shows his legs and hands during the REM sleep. Most of the infants experience the REM sleep. The sleep become less active and the individual is more conscious during the REM sleep. The breathing of the infant is quite irregular in REM sleep.
Answer:
One allele is on one chromosome, and the other is in the same position (locus) on the homologous chromosome.
Explanation:
The genotype of an organism refers to the genetic makeup or complete set of genes. The genes control the trait of an organism and exist in an organism in their alternative form called alleles.
Since the alleles are the alternative form of a gene, therefore, they must be present at the same position called a locus.
These alleles are present on the homologous chromosome in which each homologous chromosome is contributed by each parent.
Therefore when the genotype is aa then a and a allele will be present on homologous chromosomes in the same position.
Thus, the selected option is correct.
Let us assign the
recessive allele for freckle to be f and
the dominant F. According to the statement, we deduce that ff = 0.04.
The frequency of the recessive f allele is, therefore, is
0.2 (square root of 0.04 ).
Hardy-Weinburg p + q = 1
P + 0.2 = 1; p = 1- 0.2 = 0.8
Therefore using the Hardy-Weinburg equation of a population
in equilibrium
P2+2pq+q2=1
Heterozygous individuals are;
2pq = 2*0.8*0.2 = 0.32
This is 32% of the population
