Answer:
what do you need? ^-^ I can help you
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
Answer:
- 1 2/6 - 1/6
- 1 3/6
-1 1/2
Step-by-step explanation:
Answer:
x = 8
FE = 54
Its Acute, Isosceles triangle
Step-by-step explanation:
Well you have to do this out of order and use some knowledge about questions, (It always helps.)
Lets do 12 first:
If this were a scalene triangle, you wouldn't be able to solve for it. Because no sides are equal and this isn't equilateral, because it only shows two equal angles. Therefore it is Isosceles.
Also, if this were a right triangle we would see the little square for an angle. It isn't obtuse because if you look at the triangle and its angles it isn't wider than the square (this only works on the ones that are to scale like this one) So again by elimination and some knowledge of the question we figure out that it is an acute scalene triangle
Now we try and find X. Because Angles F, and E are equal, we can make the two sides equal to each other and solve for x.
Add 24 on both sides
8x - 24 = 40
+24 +24
Divide by 8 on both sides
8x/8 = 64/8
And Voilla
X = 8
Hope this helped! Ask me if you have any further questions!
