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kirill [66]
3 years ago
9

A university law school accepts 7 out of every 11 applicants. If the school accepted 665 students, how many applications did the

y receive?
Mathematics
1 answer:
Fittoniya [83]3 years ago
6 0

Answer:

1,045 applications

Step-by-step explanation:

Create a proportion where x is the number of applications they received:

\frac{7}{11} = \frac{665}{x}

Cross multiply and solve for x:

7x = 7315

x = 1045

So, they received 1,045 applications

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Answer:

The answer is -11

Step-by-step explanation:

-11 + 5 = -6

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Answer:

C).

Step-by-step explanation:

-3x+2 and[(-)(x^2+5x)

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What number is 32% of 75?
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3 years ago
Read 2 more answers
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y = 5 − x 2 . What are the dimensions
kherson [118]

Answer:

A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=5−x^2. What are the dimensions of such a rectangle with the greatest possible area?

Width =

Height =

Width =√10 and Height = \frac{10}{4}

Step-by-step explanation:

Let the coordinates of the vertices of the rectangle which lie on the given parabola y = 5 - x² ........ (1)

are (h,k) and (-h,k).

Hence, the area of the rectangle will be (h + h) × k

Therefore, A = h²k ..... (2).

Now, from equation (1) we can write k = 5 - h² ....... (3)

So, from equation (2), we can write

A =h^{2} [5-h^{2} ]=5h^{2} -h^{4}

For, A to be greatest ,

\frac{dA}{dh} =0 = 10h-4h^{3}

⇒ h[10-4h^{2} ]=0

⇒ h^{2} =\frac{10}{4} {Since, h≠ 0}

⇒ h = ±\frac{\sqrt{10} }{2}

Therefore, from equation (3), k = 5 - h²

⇒ k=5-\frac{10}{4} =\frac{10}{4}

Hence,

Width = 2h =√10 and

Height = k =\frac{10}{4}.

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3 years ago
Consider the circumscribed angle. value of x ​
musickatia [10]
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