Answer:
The option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Step-by-step explanation:
As the domain of f(x) is the set of all real values except 7. So it can be written as follows:
Domain of f(x) = { x ∈ R | x ≠ 7}
As the domain of g(x) is the set of all real values except -3. So it can be written as follows:
Domain of g(x) = { x ∈ R | x ≠ -3}
It is a common rule that the domain of a composite function (gºf)(x) will be the set of those input x in the domain of f for which f(x) is in the domain of g.
So, the option is: <em>all real values except x = 7 and the x for which f(x) = -3</em>
Keywords: domain, composite function
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<span>7q^2 − 28 = 0
</span>7q^2<span> = 28
</span>q^2<span> = 28/7
</span>q^2<span> = 4
</span>q^2= 2^2
<span>q=+ 2 and q = -2
hope that helps
</span>
Answer: 64
Step-by-step explanation:
By definition, a perfect square is the square of a whole number.
The information given in the problem that you must keep on mind is:
- The number has two digits.
- The number is a perfect square ( Is obtained by squaring a whole number).
- The sum of its two digits is 10.
The number 64 is formed by the digit 6 and the digit 4. The sum of both digits is:
The number 64 can be written as:
Then, it is perfect square.
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