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ra1l [238]
3 years ago
8

Is it possible for a segment to have more than one bisector? Explain your reasoning.

Mathematics
1 answer:
lord [1]3 years ago
6 0
Yes.

A bisector of a line segment is a line which divides the line segment into two equal parts.
A bisector of a line can divide the line in many different ways forming different angles.
A bisector is said to be a perpendicular bisector if the angle at the intersection of the two lines is 90 degrees.
But, there are several other bisectors that are not perpendicular bisectors.

Therefore, <span>it is possible for a segment to have more than one bisector.</span>
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PLEASE ANSWER THE QUESTION IN THE PICTURE BELOW
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Step-by-step explanation:

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<em>Comment on the problem</em>

Since you are given the base and height, we presume you are intended to use the formula above. You are also given all three side lengths. If you use the appropriate formula with those, you find the area is about 15.6 square inches. (The height of this triangle is actually closer to 5.2 inches.)

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2 years ago
A committee consisting of 4 faculty members and 5 students is to be formed. Every committee position has the same duties and vot
Zina [86]

<u>Answer: </u>

The number of ways to form the committee is formed = 637065

<u>Solution: </u>

The number of combinations of n things such that m things taken together are given by:-

C_{(\boldsymbol{n}, \boldsymbol{m})}=\frac{n !}{m !(\boldsymbol{n}-\boldsymbol{m}) !}

Given Data:

A committee consisting of 4 faculty members and 5 students is to be formed.  There are 12 faculty members and 13 students eligible to serve on the committee.

Then, the number of ways to form the committee is formed given by :-

\begin{array}{l}{12 C_{4} \times 13 C_{5}} \\\\ {=\frac{12 !}{4 !(12-4) !} \times \frac{13 !}{5 !(13-5) !}} \\\\ {=\frac{12 !}{4 ! 8 !} \times \frac{13 !}{5 ! 8 !}} \\\\ {\frac{12 \times 11 \times 10 \times 9 \times 8 !}{27 \times 8 !} \times \frac{13 \times 12 \times 11 \times 10 \times 9 \times 8}{120 \times 8 !}} \\\\ {=637065}\end{array}

Hence, the number of ways to form the committee is formed = 637065

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