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3 years ago

Write the integer. A debt of $20

Mathematics

2 answers:

joja [24]3 years ago

8 0

The integer for a debt of 20 is -20

kotykmax [81]3 years ago

5 0

The answer is -20 since it is in debt and dept is negative

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600,000 1/10 of what? Please help!!

igor_vitrenko [27]

600000 is 1/10 of "x", that means x = 10/10 or a whole, what is "x"?

$\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
600000&\frac{1}{10}\\\\
x&\frac{10}{10}
\end{array}\implies \cfrac{600000}{x}=\cfrac{\frac{1}{10}}{\frac{10}{10}}\implies \cfrac{600000}{x}=\cfrac{1}{10}
\\\\\\
\cfrac{600000\cdot 10}{1}=x$

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3 years ago

What is the distance between (-5, 5) and (1, -2)

Murrr4er [49]

Answer:

$\displaystyle d=\sqrt{85}\text{, or about 9.22 units}$

Step-by-step explanation:

We will use the distance formula to solve.

$\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}$

$\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}$

$\displaystyle d=\sqrt{(6)^2 +(-7)^2}$

$\displaystyle d=\sqrt{36+49}$

$\displaystyle d=\sqrt{85}\text{, or about 9.22 units}$

Read more about using the distance formula here: brainly.com/question/15691280

6 0

1 year ago

Someone please help me??

lapo4ka [179]

The standard equation of a circle with centre (xc,yc) and radius R is given by

$(x-x_c)^2+(y-y_c)^2=R^2$

Substituting
centre (xc,yc) = (4,-3)
R=2.5

The equation is therefore

$(x-x_c)^2+(y-y_c)^2=R^2$
$(x-4)^2+(y-(-3))^2=2.5^2$
$(x-4)^2+(y+3)^2=2.5^2$ or
(x-4)^2+(y+3)^2=6.25

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3 years ago

A phone sells for $250. It is now on sale for 1··5off the original price. April has a coupon for an extra 10% off the sale price

anastassius [24]

It's on a sale for 1 fifth of the original price?

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3 years ago

Brian, Alex & Colin share some money in the ratio 1:9:3.

fiasKO [112]

Answer:

Step-by-step explanation:

1:9:3

brian gets x

alex gets 9x

colin gets 3x

Brian and colin receive 40

x + 3x = 40

x = 10

alex gets 9x = £90

3 0

3 years ago