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elixir [45]
3 years ago
15

A colony contains 1500 bacteria. The population increases at a rate of 115% each hour. If x represents the number of hours elaps

ed, which function represents the scenario?
f(x) = 1500(1.15)x
f(x) = 1500(115)x
f(x) = 1500(2.15)x
f(x) = 1500(215)x
Mathematics
1 answer:
Burka [1]3 years ago
5 0

Answer:Answer:

Option (c) is correct.

function representing the increase of bacteria every hour x,

Step-by-step explanation:

Given : A colony contains 1500 bacteria. The population increases at a rate of 115% each hour.

we have to find the function that represents the given scenario.

Let x represents the number of hours elapsed.

Given  A colony contains 1500 bacteria

and number of bacteria is increasing at a rate of 115% each hour.

Using formula for Compound interest , we have,

Where A is amount

T is time period

R is rate of interest

Here, P = 1500

T = x hours

R = 115%

Let f(x) be the function representing the increase of bacteria every hour.

Substitute, we have,

Simplify, we get,

Thus,  function representing the increase of bacteria every hour x,

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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Simplify:<br> (4p3 + 6p2 – 7) – (8p? – 7 – 3p)
Kipish [7]

Answer:

4p3 + 6p2 - 8p - 7

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "p2"   was replaced by   "p^2".  1 more similar replacement(s).

STEP

1

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Equation at the end of step 1

 (((4 • (p3)) +  (2•3p2)) -  7) -  8p

STEP

2

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Equation at the end of step

2

:

 ((22p3 +  (2•3p2)) -  7) -  8p

STEP

3

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Checking for a perfect cube

3.1    4p3+6p2-8p-7  is not a perfect cube

Trying to factor by pulling out :

3.2      Factoring:  4p3+6p2-8p-7

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -8p-7

Group 2:  4p3+6p2

Pull out from each group separately :

Group 1:   (8p+7) • (-1)

Group 2:   (2p+3) • (2p2)

3.3    Find roots (zeroes) of :       F(p) = 4p3+6p2-8p-7

Polynomial Roots Calculator is a set of methods aimed at finding values of  p  for which   F(p)=0  

Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers  p  which can be expressed as the quotient of two integers

The Rational Root Theorem states that if a polynomial zeroes for a rational number  P/Q   then  P  is a factor of the Trailing Constant and  Q  is a factor of the Leading Coefficient

In this case, the Leading Coefficient is  4  and the Trailing Constant is  -7.

The factor(s) are:

of the Leading Coefficient :  1,2 ,4

of the Trailing Constant :  1 ,7

Let us test ....

  P    Q    P/Q    F(P/Q)     Divisor

     -1       1        -1.00        3.00    

     -1       2        -0.50        -2.00    

     -1       4        -0.25        -4.69    

     -7       1        -7.00       -1029.00    

     -7       2        -3.50        -77.00    

     -7       4        -1.75        3.94    

     1       1        1.00        -5.00    

     1       2        0.50        -9.00    

     1       4        0.25        -8.56    

     7       1        7.00        1603.00    

     7       2        3.50        210.00    

     7       4        1.75        18.81    

Final result :

 4p3 + 6p2 - 8p - 7

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128=(64+64+64+x)/4
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subtract 192 from both sides
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The missing number is 320..


Now lets double check our work.

Mean=(64+64+64+320)/4=512/4=128

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Substitute x by 2
Y=1
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