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Sonbull [250]
3 years ago
6

How many significant figures are in 2856.110​

Mathematics
1 answer:
Mkey [24]3 years ago
6 0

‍♀️‍♀️‍♀️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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If carbon dioxide, methane, and water vapor were not in the atmosphere, then
Savatey [412]
<h2>Answer:</h2>

D. The Earth's surface would be much colder than it is.

<h3>Step-by-step explanation:</h3>

This is because warm temperatures and high levels of atmospheric carbon dioxide happen at about the same time. So if atmospheric carbon dioxide concentrations double warm up by between 2 and 4.5 degrees Celsius. On the other hand, water vapor promotes, as the greatest contributor, to the Earth’s greenhouse effect. In this way, if carbon dioxide, methane, and water vapor were not in the atmosphere, then it's obvious that the Earth's surface would be much colder than it is.

3 0
3 years ago
Evaluate functions !!!!!
loris [4]

Answer:

g = 13

Step-by-step explanation:

Plug r = 4 into the equation

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3 0
4 years ago
Use the given facts about the functions to find the indicated limit.
oksian1 [2.3K]

Answer: Option b.

Step-by-step explanation:

 1. You can rewrite it as following:

\lim_{x\to \ -6} 2

This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 2, no matter the value of x.

\lim_{x\to \ -6} 2=2

 \lim_{x\to \ -6} 1

 This means that you must substitute x=-6 into the limit. There is not x, then the function is always equal to 1, no matter the value of x.

\lim_{x\to \ -6} 1=1

2. Then:

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3. The answer 2.

7 0
3 years ago
Read 2 more answers
The question is in the screenshot
Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < \pi/2 => tan x > 0

As 0< y <  \pi/2 => tan y > 0

We have the formula:

  • \frac{1}{sin^{2}x } =1 + cot^{2}x => \frac{1}{(8/17)^{2} } = 1+cot^{2}x => cot^{2} x=225/64

As tan x = 1/(cotx) => tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}

As tan x > 0 => tan x = 8/15

  • \frac{1}{cos^{2}y } = 1+tan^{2}y => \frac{1}{(3/5)^{2} } = 1 + tan^{2} y => tan^{2}y=\frac{16}{9}

As tan y > 0 => tan y = 4/3

As tan (x-y)= \frac{tan x - tan y}{1+ tanx * tany} =\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}  

8 0
3 years ago
Compare the pair of fractions. ( &lt;,&gt;,=) <br> 3/4__5/6
Andrew [12]

Answer:

3/4 is less < than 5/6

Step-by-step explanation:

4 0
3 years ago
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