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3 years ago

Which aspect of soil characteristics is a Munsell chart used for?

1 answer:

4 0

The answer is A) determining color

The Munsell chart uses a three-dimensional diagram, factoring value, hue, and chroma, to determine the exact nature of a color. This is not limited to soil use, and is a general guide for more properly describing a color. Its applicability to soil is that the specific color of a soil can be indicative of other properties.

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Two strong magnets were brought close to each other. They were repelling each other. Explain what must have happened.

r-ruslan [8.4K]

When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.

pls. mark brainliest am. dyning for it

8 0

3 years ago

Read 2 more answers

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how

Lunna [17]

Answer:

$9.5\; {\rm m}$ .

Explanation:

Let $u$ and $v$ denote the velocity of this hockey player before and after stopping, respectively. The question states that $u = 9.5\; {\rm m\cdot s^{-1}}$ and implies that $v = 0\; {\rm m\cdot s^{-1}$ since the hockey player has come to a stop.

The duration of this acceleration is $t = 2\; {\rm s}$ .

Since the acceleration of this hockey player was constant, SUVAT equation would apply. In particular, the SUVAT equation $x = (1/2)\, (v + u) \, (t)$ gives the displacement $x$ of this hockey player during that $2\; {\rm s}$ of acceleration:

$\begin{aligned} x &= \frac{1}{2}\, (9.5\; {\rm m\cdot s^{-1}} + 0\; {\rm m\cdot s^{-1}})\, (2\; {\rm s}) = 9.5\; {\rm m} \end{aligned}$ .

In other words, this hockey player would have travelled $9.5\; {\rm m}$ while stopping.

8 0

2 years ago

Consider a satelite in a low altitude orbit around the Earth. The gravitational acceleration felt by the satelite is very close

likoan [24]

Answer:

The orbital speed of the satellite around the earth in other to remain in perfect circular orbit in given as:

v = sqrt[(Ge*M)/R],

where Ge is the gravitational constant (Ge = 6.673 x 10^-11N/m2/kg2), M is the mass of the earth(m = 5.98 x 10^24kg), and R is the radius of the earth (R = 6.47 x 10^6m)

v = SQRT [ (6.673 x 10^-11 N m2/kg2) • (5.98 x 10^24 kg) / (6.47 x 10^6 m) ]

v = 7.85 x 10^3 m/s

Explanation:

For a satelite in a low altitude orbit around the Earth, the gravitational force is the only force acting of the said satellite keeping it is a circular orbit. To keep this satellite in perfect circular orbit, it must be moving in at a certain speed, which is dependent on the earth mass and radius. This speed can be evaluated from the expression of centripetal force(F = mv2/r). The centripetal force Fc on the satellite is equal to the gravitational force on the satellite from the earth(Fe). That is, (Ge*M*m)/R2 = (m*v2)/R, where M is mass of the earth, and m is the mass of the satellite. making v the subject of the formula, the equation become v = sqrt[(Ge*M)/R].

4 0

3 years ago

How do the full valance shells of the elements in the far right column of the periodic table affects how they react and take par

7nadin3 [17]

The full valence shell means that they do not react in chemical bonding.
The main purposes of chemical bonding is to obtain a stable structure.

Since the valence shell is stable,there is no need for chemical bonding since the whole atom is stable.

4 0

2 years ago

Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both

Nuetrik [128]

Answer:

Part a)

Width of the slit is

$a = 580 nm$