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Luba_88 [7]
3 years ago
12

A tetherball is tied to the end of a string of negligible mass. The ball is struck so that it moves in uniform circular motion i

n a horizontal plane, and the string makes an angle of 26° with the vertical pole. The mass of the ball is 1.3 kg. What is the ball's speed
Physics
2 answers:
il63 [147K]3 years ago
7 0
The centripetal force is directed parallel to the string and the weight of the ball is always directed downwards. Making a force balance along the direction of vertical axis:
Fc cos 26 = W
where Fc is the centripetal force which is equal to mv2/r
W is the weight which is equal to mg

m v2 /r cos 26= mg
v2 /r cos 26 = g
v2 = rg cos 26
v2 = 2.1(9.81) cos 26
v = 4.30 m/s

The ball's speed is 4.30 m/s.
solmaris [256]3 years ago
4 0

Answer:

v =  24sqrt{r} m/s

Explanation:

as vertical force is equal to weight,

hence W= Fc Cos 26

now ,   mass= mg

and Fc= mv^{2}/r

where r is the length of string.

putting all the values together in equation 1 :

mg = mv^{2}/r Cos 26

v^{2} = rg Cos 26

v^{2} = r (9.8) Cos 26

v^{2} = 9.8 * (.64691) r

   v =  24sqrt{r} m/s

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Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
kondaur [170]

Answer:

a) impulse = 2.5 × 10³Ns

b) average force on the passenger during the collision = 8.3 × 10⁵ N

Explanation:

Given that

Elevator cab free fall = 39.0m

The passenger = 92kg

Collision time = 3.00ms

The impulse is given by

J = Δp

= m(v_f - v_i)

where m is the mass ,

v(f) is final velocity

v(i) is initial velocity which is equal to 0

from the conservation energy system, the kinectic enegy of the passenger equal the potential energy of the pasenger

\frac{1}{2} mV^2_f = mgh

V_f = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 39  }\\ = 27.65ms\\impulse = 92 \times 27.65\\= 2.5 \times 10^3Ns

J = 2.5 × 10³Ns

b) Average force is given by

F(avg) = J / Δt

F_a_v_g = \frac{2,5 \times 10^3}{3 \times 10 ^-^3} \\8.3 \times 10^5N

average force on the passenger during the collision = 8.3 × 10⁵ N

8 0
4 years ago
A softball is thrown perfectly vertically (straight-up) at 18 m/s.
inessss [21]

Answer:

a) y = 16.51 [m]

b) t = 1.83 [s]

Explanation:

To solve this problem we must use two kinematics equations, the first to determine the height to which the ball reaches, and the second equation to determine how long it lasts in the air.

v_{f} ^{2}= v_{i} ^{2} - (2*g*t)\\

where:

Vf = final velocity = 0

Vi = initial velocity = 18 [m/s]

g = gravity acceleration = 9.81[m/s^2]

t = time [s]

Note: the negative sign of the Equation indicates that the acceleration of gravity acts in the opposite direction to the movement of the ball.  The final velocity is zero, since the ball reaches its maximum altitude when the velocity is zero.

Now replacing:

0 = (18)^2 - (2*9.81*y)

y = 16.51 [m]

b)

v_{f} = v_{i} - (g*t)

0 = 18 - (9.81*t)

t = 1.83 [s]

8 0
3 years ago
The convex len called converging lens
olya-2409 [2.1K]

What is the question?

8 0
4 years ago
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A ball is thrown vertically upward from the top of a building 80 feet tall with an initial velocity of 64 feet per second. The d
-BARSIC- [3]

Answer:

a) t=6.37s

b) t=3.3333s

Explanation:

The knowable variables are the initial hight and initial velocity

s_{o}=80ft

v_{os}=64ft/s

The equation that describes the motion of the ball is:

s=80+64t-16t^{2}

If we want to know the time that takes the ball to hit the ground, we need to calculate it by doing s=0 that is the final hight.

0=80+64t-12t^{2}

a) Solving for t, we are going to have two answers

t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a=-16

b=64

c=80

t=-1.045 s or t=6.378s

<em><u>Since time can not be negative the answer is t=6.378s </u></em>

b) To find the time that takes the ball to pass the top of the building on its way down, we must find how much does it move too

First of all, we need to find the maximum hight and how much time does it take to reach it:

v_{y}=v_{o}+gt

at maximum point the velocity is 0

0=64-32.2t

Solving for t

t=1.9875 s

Now, we must know how much distance does it take to reach maximum point

s=0+64t-16t^{2} =64(1.9875)-12(1.9875)^{2} =80ft

So, the ball pass the top of the building on its way down at 160 ft

160=80+64t-16t^{2}

Solving for t

t=2s or t=3.333s

Since the time that the ball reaches maximum point is almost t=2s that answer can not be possible, so the answer is t=3.333s for the ball to go up and down, passing the top of the building

4 0
3 years ago
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Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sou
jok3333 [9.3K]
 The solution to your problem is as follows:

speed of sound = 331.4 + 0.61 x T 
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speed of sound = 331.4 + 9.15 
<span>speed of sound = 340.55 m/s 
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
4 years ago
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