Answer:
7.0909090909 hope this helps!!
Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
Answer:
-sinx
Step-by-step explanation:
a trig identity that is crucial to solving this problem is: sin^2 + cos^2 = 1
with knowing that, you can manipulate that and turn it into 1 - sin^2x = cos^x
so 1-sin^2x/sinx - cscx becomes cos^2x/sinx - cscx
it is also important to know that cscx is the same thing as 1/sinx
knowing this information, cscx can be replaced with 1/sinx
(cos^2x)/(sinx - 1/sinx)
now sinx and 1/sinx do not have the same denominator, so we need to multiply top and bottom of sinx by sinx; it becomes....
cos^2x
---------------------
(sin^2x - 1)/sinx
notice how in the denominator it has sin^2x-1 which is equal to -cos^2x
so now it becomes:
cos^2x
--------------
-cos^2x/sinx
because we have a fraction over a fraction, we need to flip it
cos^2x sinx
---------- * ----------------
1 - cos^2x
because the cos^2x can cancel out, it becomes 1
now the answer is -sinx
ok thank you so much for the info
