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raketka [301]
3 years ago
8

Please answer! 40 points! (It will give you half of that)

Mathematics
2 answers:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

1-1

2-2

3-4

4-3

5-6

6-5

Step-by-step explanation:

Just simplify each equation to its simplest form

eg,: #1

4/3 = 1 1/3

STALIN [3.7K]3 years ago
4 0

Answer: 1 1/3=4/3

1 1/2=9/6

1 3/4=7/4

8/3=2 2/3

17/5=3 2/5

11/8=1 3/8

Step-by-step explanation:

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(HELP I BEG YOU I NEED SLEEP ITS EASY MULTIPLE CHOICE)
ivann1987 [24]

Answer:the answer will be 6

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How to do this question
RoseWind [281]
Idek hun I don’t see anything
3 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

6 0
1 year ago
for y=x^2-10 do the following . A) Sketch a graph of the equation. B) Identify the vertex. C)Compare the graph of y=f(x) to the
Andreas93 [3]
A ) A graph of the equation is in the attachment.
B ) The vertex ( 0, -10 )
C ) The graph of y = x² is translated for 10 units down.
Download docx
8 0
3 years ago
What is the perimeter of the quadrilateral shown below?
GarryVolchara [31]

The perimeter of a shape is the sum of the lengths of its sides.

So, to find the perimeter of this quadrilateral, all we have to do is add the side lengths and simplify.

(x² - 6) + (2x + 5) + (x² - 3x) + (4x² + 2x)

x² + x² + 4x² + (-3x) + 2x + 2x + (-6) + 5

6x² + (-3x) + 2x + 2x + (-6) + 5

6x² + x + (-6) + 5

6x² + x + (-1)

6x² + x - 1

So, the perimeter of the quadrilateral is the quantity (6x² + x - 1).

Hope this helps!

8 0
3 years ago
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