Answer:
3.5
Step-by-step explanation:
If the shape is half of a circle, you will be using this formula: A = π
Your radius is half of the diameter. r = d/2 = 3/2 = 1.5
Substitute r = 1.5 into the formula.
A = π
A = (3.14)
Use your calculator to find the answer and round your answer.
3.5
A bengal tiger the male is : 180-258kilograms and 397-569 pounds FOR FAMALE:100-160 kilograms and 220-353 pounds THEASE ARE FOR BENGAL TIGER BUT YOU WHANT A BENGAL TIGER OR SABIRIAN TIGER BUT I JUST GAVE YOU MORE INFORMATION IS 300 KILOGRAMS
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Answer:</u></h2><h2>
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<u>Solution Steps: </u></h2><h3>- Steps for solving linear equations - </h3>
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</u></h2><h3>1.) <u>Divide both sides by 5:
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- ÷ Cancels out
<em> - I changed </em><em> to a fraction instead, and you'll see why on the next step. </em>
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2.) <u>
Add 4 to both sides:</u></h3>
- Cancels out
<em> - 4 in fraction form would best be </em><em> in this situation. </em>
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3.) <u>Add: </u></h3>
<em> - Since </em><em> and </em><em> have the same denominator, all you have to do is add the numerators. </em>
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4.) <u>Simplify:</u></h3>
- Improper fraction form:
- Mixed number form:
- Decimal form:
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Solve for
x
x in
3
x
−
6
y
=
−
12
3x−6y=−12.
x
=
2
y
−
4
x=2y−4
2 Substitute
x
=
2
y
−
4
x=2y−4 into
2
x
−
4
y
=
−
16
2x−4y=−16.
−
8
=
−
16
−8=−16
3 Since
−
8
=
−
16
−8=−16 is not true, this is an inconsistent system.
No Solution
Answer: Each bow needs 4.67 yards of ribbon.
Step-by-step explanation:
We know that each roll has 20 yd.
She used 3 + 1/2 rolls, then the total length used will be (3 + 1/2) times the length of each roll, this is:
(3 + 1/2)*20 yd = (6/2 + 1/2)*20yd = (7/2)*20yd = 70 yd.
With tose 70 yards of ribbon, she made 15 bows, then the length of ribbon used in each bow will be equal to the quotient between the total length used and the number of ribbons made with it, this is:
70yd/15 = 4.67 yards
Each bow needs 4.67 yards of ribbon.